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Please help! I am trying to make a CList of CUIntArray. Add a CUIntArray to the list, read the CUIntArray from the list and TRACE it to the debug window! Here is the code however when I try to compile i get the error...
'CUIntArray' : 'operator =' function is unavailable.... Please Help! 
CString debug;
CUIntArray array;
CList <cuintarray,cuintarray&> list; // create the list
array.SetSize(3);
for (int x=0;x<3;x++)
{
array[x]=0;
}
list.AddTail(array); //create array and add to the list
POSITION pos=list.GetHeadPosition(); // get start position of list
int arraylength;
while (pos!=NULL)
{
list.GetNext (pos);
arraylength=(list.GetAt(pos)).GetSize();
for (int x=0;x
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Which use of = ? Which line is the error occuring on?
--Mike--
My really out-of-date homepage
"Not our fault we are intellectually superior to the rest of the office." -- Paul Watson in the Lounge, 12/12/2001
Sonork - 100.10414 AcidHelm
Big fan of Alyson Hannigan.
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I think it has something to do with
CUIntArray=CUIntArray causing a problem
the only way i can think to remedy this is to use a CStringList, and convert between characters and integers
template<class type,="" class="" arg_type="">
POSITION CList<type, arg_type="">::AddTail(ARG_TYPE newElement)
{
ASSERT_VALID(this);
CNode* pNewNode = NewNode(m_pNodeTail, NULL);
pNewNode->data = newElement; ////// this is where the error is!
if (m_pNodeTail != NULL)
m_pNodeTail->pNext = pNewNode;
else
m_pNodeHead = pNewNode;
m_pNodeTail = pNewNode;
return (POSITION) pNewNode;
}
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i've found that this code can be used which when implemented is identical to the CList of CUIntArray.....
CString debug,str;
CStringList list;
for (int x=0;x<3;x++)
for (x=0;x<3;x++)
str.Insert(x,static_cast <char>(0)); // create string containing integer after convertion to character
AfxMessageBox(str);
list.AddTail(str); // add string to CStringList
POSITION pos=list.GetHeadPosition(); // get start position of list
for (x=0;x<list.getat(pos).getlength();x++)
{
=""
="" debug.format(="" "%d="" ",static_cast="" <int="">(list.GetAt(pos).GetAt(x)) ); // Get character from list convert to integer
TRACE (debug); //// display on Debug window with trace
}
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I am trying to set the background color of a mini server to that of the container. Can I access the container's ambient properties from MFC's COleServerItem class? How is this typically done?
Thanks
~ Paul ~
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Hi,
I find there is a slight inconvenience with the std::getline function in C++. Here is an example:
-----------------------------------------------------------
#include <iostream>
using std::cin;
using std::cout;
using std::endl;
using std::getline;
#include <string>
using std::string;
int main()
{
string strTemp;
cout << "Enter a sentence: ";
getline(cin, strTemp);
cout << "\nYou entered: "
<< strTemp << endl;
return 0;
}
-----------------------------------------------------
If you run the code above, and hopefully I did not leave anything out, out will find that after you entered a sentence and press Enter, the "cursor" will go to the next line, but the program does not move onto "You have entered: " until you press Enter the second time. In other words, I have had problems with the getline function in term of having to press Enter twice to get it to move onto the next algorithm.
I have tried for example:
getline(cin, strTemp, '\n');
It has the same effect.
Is there a way to get around having to press Enter twice?
Thanks,
Kuphryn
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Probably, you're running into a known bug in Dinkumware's implementation of the C++ standard library. This article addresses the problem (look for the "Fix to <istream>" section) and proposes a fix.
Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo
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zen from cprogramming.com posted something about a bug in VC++:
http://www.cprogramming.com/cboard/showthread.php?s=a4253030337e8f0dc4d9e68fb761087c&postid=48172#post48172
That fixed the problem.
Kuphryn
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Hi.
I am working on a simple program that reads data into memory in binary. It then write the data from memory to a second file in memory.
Is it possible to read from ifstream straight to an STL container instead of having to go through dynamic memory allocation?
Thanks,
Kuphryn
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Yes.
You can read a file into a
<br />
vector<char> data;<br />
<br />
or<br />
<br />
string data;<br />
can use istreambuf_iterator to load the file
<br />
ifstream file("c:\\somefile");<br />
vector<char> data((istreambuf_iterator<char>(file)), istreambuf_iterator<char>());<br />
you can make it faster by getting the file size and using dat.reserve() to pre-allocate the required memory.
Todd Smith
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Thanks.
Okay, this is more advanced STL than I am used to. I have no prior knowledge of istreambuf_iterator or ostreambuf_iterator.
First will:
vector data((istreambuf_iterator(file)), istreambuf_iterator());
read data from a file into vector data in *binary* mode?
I am used to something like:
--------------------
char x[5];
istream data;
data.open(x, ios::in | ios::binary);
data.read(reinterpret_cast<char *="">(x), 5);
--------------------
The same goes for data.reserve("size???").
Kuphryn
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Can anyone help with a nice algorithm to create a gradient style color ramp?
What I need is to specific the first and last colors and generate a specified number of colors between them.
Best regards,
Paul.
Paul Selormey, Bsc (Elect Eng), MSc (Mobile Communication) is currently Windows open source developer in Japan, and open for programming contract anywhere!
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This is what I use :
COLORREF *Gradient(COLORREF start, COLORREF end, int steps)
{
if (steps < 2)
return NULL;
COLORREF *output = new COLORREF[steps];
output[0] = start;
output[steps - 1] = end;
double sR = (double)GetRValue(start);
double sB = (double)GetBValue(start);
double sG = (double)GetGValue(start);
double eR = (double)GetRValue(end);
double eB = (double)GetBValue(end);
double eG = (double)GetGValue(end);
double RedStep = (eR - sR) / (double)steps;
double BlueStep = (eB - sB) / (double)steps;
double GreenStep = (eG - sG) / (double)steps;
for (int x = 1; x < steps - 1; x++)
{
sR += RedStep;
sB += BlueStep;
sG += GreenStep;
output[x] = RGB((BYTE)sR, (BYTE)sB, (BYTE)sG);
}
return output;
}
---
It may be that your sole purpose in life is simply to serve as a warning to others.
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(I previewed this before posting it, but I don't know why the blank lines are missing from the pre section.)
void RampColours(int nColourCount, COLORREF crLowColour, COLORREF crHighColour, COLORREF* pColourTable)
{
double red_step, green_step, blue_step;
int red_low, green_low, blue_low;
red_low = GetRValue(crLowColour);
green_low = GetGValue(crLowColour);
blue_low = GetBValue(crLowColour);
red_step = (double)(GetRValue(crHighColour) - red_low) / (double)nColourCount;
green_step = (double)(GetGValue(crHighColour) - green_low) / (double)nColourCount;
blue_step = (double)(GetBValue(crHighColour) - blue_low) / (double)nColourCount;
pColourTable[0] = crLowColour;
pColourTable[nColourCount] = crHighColour;
for (int i = 0; i <= nColourCount; i++) {
pColourTable[i] = RGB( red_low + (red_step * (double)i), green_low + (green_step * (double)i), blue_low + (blue_step * (double)i) );
}
}
"Am I talking too fast, or are you just playing dumb? If you want I can write it down." -Jarvis Cocker/Pulp
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Here is another one. This is from a little app I hope to be posting here soon :
<br />
BYTE InterpColor( BYTE top, BYTE bottom, int linendx, int maxlines )<br />
{<br />
if( top == bottom )<br />
return top;<br />
<br />
double cval = (double)linendx * (double)( bottom - top ) / (double)maxlines;<br />
cval += (double)top;<br />
return (BYTE)cval;<br />
}<br />
<br />
<br />
void GetGradientColor( int count, int index, COLORREF top, COLORREF bottom )<br />
{<br />
BYTE r = InterpColor( GetRValue( top ), GetRValue( bottom ), index, count );<br />
BYTE g = InterpColor( GetGValue( top ), GetGValue( bottom ), index, count );<br />
BYTE b = InterpColor( GetBValue( top ), GetBValue( bottom ), index, count );<br />
COLORREF color = RGB( r, g, b );<br />
return color;<br />
}<br />
<br />
This is not the absolutely most efficient algorithm but it works well for me. There are some easy optimizations that could be made but I have never seen the speed of this to be a problem.
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Rick York wrote:
void GetGradientColor( int count, int index, COLORREF top, COLORREF bottom )
That's nice, but what about some dithering? Does anyone know how to implement one (at least of 'ordered' style)?
* Origin: Silence Must Be Heard (2:5030/844.235)
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Hello All,
Thanks so much for coming quickly to my aid. May God bless you all.
Best regards,
Paul.
Paul Selormey, Bsc (Elect Eng), MSc (Mobile Communication) is currently Windows open source developer in Japan, and open for programming contract anywhere!
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Hi, i have a problem, there are a lot of interesting activex controls - but they are loaded dynamicaly (or not?) so i'm not sure if all the users will have them - can you help me - are there some ActiveX controls that are installed on every win machine ? For example there is "Microsoft Forms Checkbox" (or socalled) is it available on every win-box ?
thanks a lot for explanation
john
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- Can you help?
- Regards,
BigMouth
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- Thanks, Mike pal!
- I do not know what you mean? Do you mean "http://comp.os.linux.*" ? How to check? I am a newbie. Can you help?
- Have a nice day,
Maer
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It means newsgroups with names starting with "comp.os.linux". Newsgroups aren't WWW pages, so there's no "http://". Use your newsreader program (Outlook Express, Forte Agent, etc. under Windows) and subscribe to groups in the comp.os.linux hierarchy. If your ISP doesn't support newsgroups, you can use Google Groups (http://groups.google.com).
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- Thanks pal!
- I have known what you mean.  I think there are a lot of news groups that conform to your conditon. (starting with "comp.os.linux")
- Can you introduce some of them that is best for newbies?
- Regards,
BigMouth
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I have found the registry entries for the timezone list and the current Timezone setting. I am assuming (maybe incorrectly) that MS use these two areas to setup the timezone selection combo box in the timedate.cpl aplet. The problem is that you can't rely on the bias entry because more than one entry may be present with the same bias. The strings are different in both areas (as in AUS Eastern Std Time) so how do they select the correct one??
Happy programming!!
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I don't quite understand what you are trying to do, but perhaps you should be calling the GetTimeZoneInformation function?
"Am I talking too fast, or are you just playing dumb? If you want I can write it down." -Jarvis Cocker/Pulp
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