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Why handler WM_NCLBUTTONDOWN inside CEdit does not receive the notify at click of the mouse outside it?
Best regards,
Eugene Pustovoyt
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From MSDN
WM_NCLBUTTONDOWN
The WM_NCLBUTTONDOWN message is posted when the user presses the left mouse button while the cursor is within the nonclient area of a window. This message is posted to the window that contains the cursor. If a window has captured the mouse, this message is not posted.
Michael 
Communication is the first step towards enlightenment.
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I'm not capture the mouse!!!
Eugene Pustovoyt
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Hi Eugene,
The WM_NCLBUTTONDOWN message is only generated when a mouse is clicked on the nonclient area of the edit control (ie. the border, the one or two pixel wide area around the client area), it is not generated when the mouse is clicked outside the control.
What Michael was refering to is that once the mouse has been captured (via SetCapture()), all mouse messages are treated as client area mouse messages for the window that has captured the mouse.
HTH
---
CPUA 0x5041
Sonork 100.11743 Chicken Little
If a man is standing in the middle of the forest speaking and there is no woman around to hear him...is he still wrong?
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Thank you PJ!!!
That is I do not have other exit to determine, what click outside the control except for as through capture of the mouse has been made?
If yes, where it is better to me to grasp the mouse if it is necessary for me, that it has been captura after his creations?
P.S. Thank you for your CFileEditCtrl & CPJAImage
Best regards,
Eugene Pustovoyt
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If you want to know if the mouse is clicked outside the edit control, capture it with SetCapture(), then handle WM_LBUTTONDOWN and check the point is in the rectangle returned by GetWindowRect() using PtInRect(). Just remember that GetWindowRect() is in screen coords and WM_LBUTTONDOWN is in client coords.
HTH
---
CPUA 0x5041
Sonork 100.11743 Chicken Little
If a man is standing in the middle of the forest speaking and there is no woman around to hear him...is he still wrong?
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It is clear! Probably at click of the mouse outside the control, I need call method ReleaseCapture, as I want to remove in this case itself edit! Is it correctly?
But I have one more question! I need capture the mouse at creation edit then to trace all possible clicks behind his limits. Where it to make, i.e. SetCapture the mouse?
I apologize for my English 
Eugene Pustovoyt
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Eugene Pustovoyt wrote:
Probably at click of the mouse outside the control, I need call method ReleaseCapture, as I want to remove in this case itself edit! Is it correctly?
Yes
Eugene Pustovoyt wrote:
Where it to make, i.e. SetCapture the mouse?
Not knowing exactly what you are doing, I would recommend capturing the mouse in your WM_SETFOCUS handler ( OnSetFocus() )
HTH
---
CPUA 0x5041
Sonork 100.11743 Chicken Little
If a man is standing in the middle of the forest speaking and there is no woman around to hear him...is he still wrong?
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PJ Arends wrote:
Not knowing exactly what you are doing
I create a class derivative from CEdit inside which on click of the mouse I am created in-place edit. Him also I want to delete at click of the mouse not on him.
PJ Arends wrote:
I would recommend capturing the mouse in your WM_SETFOCUS handler ( OnSetFocus() )
Method OnSetFocus probably will approach.
Thank you for Your Help!
Best regards,
Eugene Pustovoyt
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Hi,
I think you're misinterpreting the WN_NCLBUTTONDOWN message. It does not detect clicks outside the client area. It detects clicks on the non-client area.
For example, if you add that handler to your main window and you click on an empty space in the menubar, the event will fire.
So basically, that event is useless for an edit because an edit does not have a non-client area.
If you're trying to detect mouseclicks outside the edit, maybe you should just add a handler for WM_LBUTTONDOWN to the edit's parent window.
P.e.a.c.e.,
Ren
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Hi,
Thanks, for the answer
Processing WM_LBUTTONDOWN in a parental class is a special case, I wanted that edit itself was destroyed at click of the mouse outside of it
Best regards,
Eugene Pustovoyt
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How can I convert GDI region object to GDI+ path object ? Any clue.
Sanju
The wizard
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The only thing that I know of is to decompose a region into all of the separate rectangles it contains, further decompose the rectangle into its points, and find the concave hull that the resulting polygon creates. The only problem with this is you will have to figure out another way to find the holes in the region.
Build a man a fire, and he will be warm for a day
Light a man on fire, and he will be warm for the rest of his life!
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When I draw a graph in the CView every time, the available memory decrease accordingly. How to release the memory of the previous graph?
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I draw graph in the CView,and I have overloaded OnEraseBkgnd and maken it return TRUE.But, when certain dialog move upon the CView, it flash very much.My code is following:
void CMyView::OnDraw(CDC* pDC)
{
CRect rect;
GetClientRect(&rect);
pDC->FillSolidRect(rect,ManExp.m_BackGroundColor);
}
However,when a dialog move on the frame of a window,the frame don't flash,why?
How to make it not flash?
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You're must create the context device in the memory.
Fill him, and then bitblt him to the CDC.
Best regards,
Eugene Pustovoyt
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I have added a toolbar to a dialog box and I wanted to 'Enable/Disable' and 'push in/pop out' the buttons to show the current status.
I have achieved this in the past within the Main Frame toolbar using a user interface (UI) handler function, but although I can add this function it never seems to get called.
Is this because the toolbar is attached to the dialog box, or am I doing something stupid?
Any help appreciated, thanks
ali p
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ali p wrote:
Is this because the toolbar is attached to the dialog box
Yes. OnUpdateCmdUI() will not be called for the toolbar. You can call it yourself if you really want to do it that way, or you can just use GetToolBarCtrl().EnableButton(), GetToolBarCtrl().CheckButton(), etc.
--------
When will I realize that this skin I'm in
Hey, it isn't mine
And when will the kill be too much meat for me to hide on... -- Blind Melon, Skinned
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Thanks, I gave this a go and got it working. Great.
ali p
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Hi,
I've written a small code (the one given in
MSDN) for capturing video from a camera...
The problem is that i can capture it well..
but when i press the stop button.. the
Camera is not switched off..
Can anybody tell me why???
I am using DirectX (DirectShow)
Please help
Sameer
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Hi everyone. I know this is a bit of a beginner question, but I never had to do this task before and am a bit confused as the best way to do it. I have a button on a dialog, which I want to place a bitmap on (specifically, the little printer bitmap under the graphics/bitmaps directory of VC++). I can either make a CButton object, and do it this way, or use CBitmapButton. I want the button to work like a toolbar button (that is, in the way it looks, and the fact only 1 bitmap is used for all button states, not the up to 4 that CBitmapButton uses).
I was going to use a CButton and place a bitmap on it, but I couldn't figure out how to get my bitmap (which is in the resource file as IDC_BMP_BITMAP) into an HBITMAP parameter, which CButton requires. I tried using CBitmap to get a HBITMAP handle back, but I couldn't quite figure out how to do this. I am sure this is a simple procedure, but it has me stumped tonight  Thanks in advance for any help!
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I used a class very very useful : CxSkinButton
If you want to have button of every shape and bitmap, try this link and I think you'll be surprised...;)
http://www.codeproject.com/buttonctrl/CxSkinButton.asp
Maybe you could tell me something too ?...
Actually I'm trying to display more than one bmp at the same location but it doesn't work properly...
I use the SetWindowPos function to place the bitmap and stretch it (or shrink it) to the correct size. It works well for the position and the size but not for the Z-Order (the first is over the second and I want the contrary). Setting the first parameter of the SetWindowPos to '&wndTop' does not change anything.
If you could help me...
Should computing stay as a source of benefit or become like knowledge : free and opened to every one ?...
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... that would work on two keys, public and private, but not like RSA, where message can be encrypted using public key and decrypted using private key. Public key should be able to decrypt message and only private key would be able to encrypt it. I could use RSA and distribute private key, but i think that it is possible to generate public key from private key. Am i wrong?
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In RSA, messages encrypted with private key can be decrypted with the public key, that's how RSA is used for digital signatures.
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