C / C++ / MFC

Re: Read a byte stream into separate buffers. [modified]

5-Dec-07 22:22

Hi all,

I have a byte stream, consisting of two parts. First 4 bytes gives an int value. Rest of the part give just a name. I want to read them separately.

I've tried something like this.

<br />
UINT vBuffer[4];<br />
::memcpy(vBuffer,InMsg.GetDataBuffer(),sizeof(vBuffer));<br />

used memcpy to copy the first 4 bytes to my buffer. Now I have two question. How read the vBuffer and find the value? How to read the rest?

I appreciate your help all the time...
Eranga Smile | :)

toxcct5-Dec-07 22:31

5-Dec-07 22:31

you say the first 4 bytes give an int value, but you don't read 4 bytes, you read 4 UINTs (that means, 16 bytes on a 32 bits system, and 32 bytes on a 64 bits system).

moreover, you're writing into an undefined buffer.

why don't you just do this:

<font color="green">//The 4 bytes buffer</font>
<font color="blue">unsigned long</font> nSize = 0;
 
<font color="green">//The 4 bytes extract</font>
::memcpy(&nSize, InMsg.GetDataBuffer(), <font color="blue">sizeof</font>(nSize));

then you don't have much complicated task to read the size...

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modified on Thursday, December 06, 2007 5:24:09 AM

CodingLover5-Dec-07 22:51

5-Dec-07 22:51

Ok, I got the point where I'm going wrong.

I have a question on your code. in memcpy first argument should be the new buffer to copy from the existing buffer. But here nSize is not a buffer at all. Can you clear me on it.

I appreciate your help all the time...
Eranga Smile | :)

toxcct5-Dec-07 22:55

5-Dec-07 22:55

oh god, you're right. i updated my previous answer so that the 4 bytes are written at the memory used by the nSize variable

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CodingLover5-Dec-07 23:04

Re: Read a byte stream into separate buffers. [modified]

5-Dec-07 23:04

How about my second question. I know that after reading the initial 4 bytes of the stream, stream points to the next byte start position. Since the length of the rest vary how can I read as u said. It's string, just a name like "ball, house, etc...."

I appreciate your help all the time...
Eranga Smile | :)

toxcct5-Dec-07 23:05

5-Dec-07 23:05

what about using strncpy() and pass it the integer formerly extracted ?

<font color="green">//The 4 bytes buffer</font>
 nSize = 0;
 
<font color="green">//The 4 bytes extract</font>
::memcpy(&nSize, InMsg.GetDataBuffer(), <font color="blue">sizeof</font>(nSize));
 
char* pszBuffer = new char[nSize + 1];  <font color="green">//+1 is for the trailing \0 character</font>
::strncpy(pszBuffer, <font color="green">/* your source data */</font>, nSize);
pszBuffer[nSize] = <font color="gray">'\0'</font>;
std::string strData = pszBuffer;
delete[] pszBuffer;

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modified on Thursday, December 06, 2007 5:15:54 AM

CodingLover5-Dec-07 23:15

5-Dec-07 23:15

Yep, initially I thought about this. But failed to do it. Because my destination is a string, that is my requirement. But my destination is in a buffer, a byte stream. I want to read it after finding the int value.

toxcct wrote:
pass it the integer formerly extracted ?

I'm not clear this.

I appreciate your help all the time...
Eranga Smile | :)

toxcct5-Dec-07 23:19

5-Dec-07 23:19

i don't understand your problem... why can't you use strncpy() ?

you say you want to read it after getting the int value, but isn't it what i'm doing there ?

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CodingLover5-Dec-07 23:48

5-Dec-07 23:48

No, No.

You take me wrong way. There is no connection between int value and the string. Let me explain it again.

Stream has two parts. First part give an int value. It gives the first 4 bytes of the stream. That is ok.

Second part has a string, few characters. I want to read it as well and find the word there has.

No connection with int value(nSize according to your code) and the string.

Is it clear...

I appreciate your help all the time...
Eranga Smile | :)

toxcct5-Dec-07 23:54

5-Dec-07 23:54

ok, so, the int is not the size of the remaining string. then just extract the string without taking care of nSize. can't you ?

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CodingLover6-Dec-07 0:00

6-Dec-07 0:00

toxcct wrote:
ok, so, the int is not the size of the remaining string.

Yes, that is correct.

toxcct wrote:
then just extract the string without taking care of nSize. can't you ?

That's where I'm stuck with. Can give me a help.

I appreciate your help all the time...
Eranga Smile | :)

toxcct6-Dec-07 0:07

6-Dec-07 0:07

Eranga Thennakoon wrote:
Can give me a help

yes, i can; that's what i'm trying to do. but i need more infos.

1) so, to begin, what have you tried so far to extract the string ?

2) is the string of a constant length ?

3) can you know its length by any method ?

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CodingLover6-Dec-07 0:28

Re: Read a byte stream into separate buffers. [modified]

6-Dec-07 0:28

toxcct wrote:
1) so, to begin, what have you tried so far to extract the string ?

Lots of things I've tried,

<br />
		char* varBuffer = new char[(InMsg.GetDataLength() - 4)];<br />
		string var_name(&InMsg[3], (InMsg.GetDataLength()-4));<br />

It is better to provide more details. InMsg is in BYTE* to a byte steam. GetDataLength() and GetDataBuffer() are two member functions to get the message and the length. Here in this case my message is included both int value and the string.

toxcct wrote:
2) is the string of a constant length ?

No, string is not in fixed length. Actually contain some small words.

toxcct wrote:

3) can you know its length by any method ?

Yes, string length is less than 4 bytes. (InMsg.GetDataLength()-4)

I appreciate your help all the time...
Eranga Smile | :)

toxcct6-Dec-07 1:55

6-Dec-07 1:55

is the string is nul-terminated ?

also, what is the type of InMsg ???

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modified on Thursday, December 06, 2007 8:08:09 AM

CodingLover6-Dec-07 17:28

6-Dec-07 17:28

toxcct wrote:
is the string is nul-terminated ?

Yes.

toxcct wrote:
what is the type of InMsg ???

The type is BYTE*

I appreciate your help all the time...
Eranga Smile | :)

jhwurmbach6-Dec-07 4:11

jhwurmbach

6-Dec-07 4:11

std::string second_part( (char*)(InMsg+sizof( first_part), InMsg.GetDataLength() - 4))

This calls the constructor of std::string with the address of the first char of the string (InMsg is of type BYTE*? So you need to cast it to char*) and the length of the remaining buffer.

Let's think the unthinkable, let's do the undoable, let's prepare to grapple with the ineffable itself, and see if we may not eff it after all.
Douglas Adams, "Dirk Gently's Holistic Detective Agency"

CodingLover6-Dec-07 17:31

6-Dec-07 17:31

Yes, I don't have cast it.

jhwurmbach wrote:
(InMsg+sizof( first_part)

I've not clear this part. Why did you add the first part length.

I appreciate your help all the time...
Eranga Smile | :)

CodingLover5-Dec-07 23:39