C / C++ / MFC Discussion Boards

voda8-Jul-05 5:10

8-Jul-05 5:10

Hi,

I created an executable with Visual c++. At some point I had to change the
icon of the file (\res subdirectory). Now, the new icon was immediately
shown on the computer I use to run Visual c++. The problem is on two
computers that are used to evaluate the tool I am developing. No matter
what I do the old icon is used by Windows Explorer and is shown in the
top left corner of the application window.

Now, if I copy the executable file to a server on the network, the new
icon is used by Windows Explorer on some workstations and the old one
on the others. My guess is that a computer gets somehow infected by the
old icon by I can not prove that becose I have run out of Windows
workstations in our network

Regards
Andrej

Re: Icon of an executable file

David Crow8-Jul-05 5:40

David Crow

8-Jul-05 5:40

voda wrote:
At some point I had to change the
icon of the file (\res subdirectory).

Exactly how did you go about changing it? My guess is that you only changed one of the resolutions (e.g., 16x16) rather than all of them (16x16, 32x32, 48x48).

"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown

Re: Icon of an executable file

Blake V. Miller8-Jul-05 16:44

Blake V. Miller

8-Jul-05 16:44

Here is a start from MSDN "Customizing Icons":

In this example, the icon is in the c:\MyDir\MyProgram.exe file, with an index of two. The registry entry that assigns the custom icon to all .myp files is as shown here.

HKEY_CLASSES_ROOT
.myp
(Default) = MyProgram.1
MyProgram.1
(Default) = MyProgram Application
DefaultIcon
(Default) = C:\MyDir\MyProgram.exe,2

Finally, call SHChangeNotify to notify the Shell to update its cache.

I am not sure what parameters to use with the SHChangeNotify function. Maybe you can enlighten us when you figure it out?

VC7, PROPVARIANT, #import

peterchen8-Jul-05 4:41

peterchen

8-Jul-05 4:41

I am trying to port a largish VC6 project to VC7/VC8 beta. Problem:

I have an .idl file with an interface definition using a PROPVARIANT structure (which is now defined in propidl.idl)

The resulting type library is imported in the client using an #import statement.

In VC7, the interface gets declared with a nnamespace_TLB::__tag_inner_PROPVARIANT type,which is not related to the PROPVARIANT coming from windows headers (which in turn breaks all my code)

Pandoras Gift #44: Hope. The one that keeps you on suffering.
aber.. "Wie gesagt, der Scheiss is' Therapie"
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Multithreaded Client

vadimpl8-Jul-05 4:32

vadimpl

8-Jul-05 4:32

I'm writing application to connect one client to multiple servers (to send the same data to several servers).
I now how to make server to manipulate with many clients, but no how to send data to many servers in the proper way.

So, Is there a way to connect and send data to multiple servers from one client.

Do you have any example to help me?

Thank you.

Re: Multithreaded Client

Ravi Bhavnani8-Jul-05 11:43

Ravi Bhavnani

8-Jul-05 11:43

You could round-robin the connections from your client to each server in turn, or create multiple threads, each of which sends data to a single client.

/ravi

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Double pointers question

Budric B.8-Jul-05 4:06

Budric B.

8-Jul-05 4:06

Hi,
I have this problem I can't find much information about. Suppose I have the following function:

void test(float arg[][3])
{
	//do nothing
}
...
float ** vertices = Allocate2DArray(10,3);  //assume that's correct
test(vertices); //doesn't work!
...
float vertices2[10][3];
test(vertices2); //works

So basically in the first case it can't convert ** to [][3]. What's the difference? How can I cast it? I can't change the function because the real one is already written that way.

Finally a question about freeing the memory. Suppose I have

BYTE * temp = new BYTE[TotalSize]
float ** result = (float **) temp;
..followed by a loop to assign result[i] = (float *) to a location in temp[i*cols*sizeof(float)];

Now if I type delete[] result. Will that delete all the memory I allocated? After all I allocated a BYTE[], but then just did a bunch of assignments.
Thanks.

Re: Double pointers question

David Crow8-Jul-05 5:37

David Crow

8-Jul-05 5:37

Budric B. wrote:
What's the difference?

Even though they can sometimes be used interchangeably, pointers and arrays are not the same thing. One way to achieve what you want is like:

double (*vertices)[3] = (double (*)[3]) malloc(10 * sizeof(*vertices));
for (int x = 0; x < 10; x++)
{
    for (int y = 0; y < 3; y++)
        vertices[x][y] = 0.0; // initialize 'em
}
 
test(vertices);

"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown

Re: Double pointers question

John R. Shaw8-Jul-05 10:13

John R. Shaw

8-Jul-05 10:13

FIRST PART:
If test(float* in){...}

vertices2 // is a pointer
test(vertices2) // ok
test(&vertices2) // error

vertices // is a pointer to a pointer
test(*vertices) // ok
test(vertices) // error

In this case a pointer to array of pointers, it gets a bit confusing.

float* pr = vertices[r];
float f = pr[c];
Therefore,
float f = (vertices[r])[c];

SECOND PART:
(*result)[i] == temp[i]
result[i] == &temp[i]

No the == are not typos.

I hope that helps.

INTP
"The more help VB provides VB programmers, the more miserable your life as a C++ programmer becomes."
Andrew W. Troelsen

Re: Double pointers question

Toby Opferman8-Jul-05 10:31

Toby Opferman

8-Jul-05 10:31

So, what is the difference between ** and [x][y]? Well, one is a static memory location and the other are pointers.

float **x;
float y[10][3];

x is a pointer to a pointer. So, what the compiler does it it goes to the address of the variable X. It then reads this address and then goes to the address stored at that location. It then uses this address as the place to store the float!

If you understand single pointers you can see how the double pointer works:

First Address = *x;
Second Address = *First Address;
The Actual Float Value = *Second Address;

At any level you can actually allocate a "block" of pointers that you can index into at that time.

So what's the difference with an array?

    y[1][2] = 12;

Is actually

    y[3 + 2] = 12;

It's a single block of memory! There are no pointers! In the case of even a single float *, the address of the variable stores the address that then stores the actual value! In the case of an array, the address of the variable stores the actual value!

So, a multi-dimentional pointer is actually a single block of memory that is then index by the compiler as one block. So if you have: rows by columns:
float x[row][column]

each row is maxcolumns size. So if you want to go to rowx, coly, you could simply do rowx*maxcolumns + coly. This would index that block of memory.

The compiler knows how to generate the correct code if it's an array or pointer. Remember, an array's address stores the actual data. The pointer's address, stores another address. That address then stores the data (in a single indirection case).

8bc7c0ec02c0e404c0cc0680f7018827ebee

Displaying MFC dialog

cdm5z8-Jul-05 3:39

cdm5z

8-Jul-05 3:39

Hey. I'm new to MFC. Here's the situation... I've got a DLL that's using shared MFC. I just want a my dialog to appear when a method in the DLL is called.

I've declared
AFX_MANAGE_STATE(AfxGetStaticModuleState());

in the method. The dialog has a class Dialog that extends CDHtmlDialog. In the method I have

Dialog dlg;<br />
dlg.DoModal();

What else is needed to make it appear? Does there need to be an object extending CWinApp, or can I just use the dialog by itself? If there has to be a CWinApp, do I need to declare it in the method or global in the DLL (I've tried both ways and neither works.)?

Many thanks for any help.

Re: Displaying MFC dialog

Manfred Staiger8-Jul-05 3:55

Manfred Staiger

8-Jul-05 3:55

You need to start your project as a "regular DLL", not as "extension DLL". Then you can, simly spoken, work as it would be a normal Application. It has a CWinApp derived application object and you can use it with any kind of application.
An extension Dll does not have a CWinApp derived object. It uses the one from the client application, which leads to soms restraints.
Serch MSDN for more information, my english is too poor to explain it better.

MS

Re: Displaying MFC dialog

cdm5z8-Jul-05 4:03

cdm5z

8-Jul-05 4:03

It is a regular DLL. What I'm wondering is if I NEED the CWinApp object at all. Can I not just do something like

Dialog dlg;<br />
dlg.DoModal();

and have that dialog appear? I've also tried making the dialog appear when InitInstance() is called in a globally declared CWinApp.

Dialog dlg;<br />
m_pMainWnd = &dlg;<br />
int result = dlg.DoModal();<br />

This doesn't make the dialog appear either. This works in an MFC application I've made, but when the same code is used in the DLL it doesn't work.

Thanks.

Re: Displaying MFC dialog

Manfred Staiger8-Jul-05 4:19

Manfred Staiger

8-Jul-05 4:19

1) You need a CWinApp derived object because it provides the main message pump, the idle loop, and so on.

2) If "Dialog" in your example is a CDialog derived class (with dialog resource assigned) it should work.

MS

CWnd::Create -> program terminates immediately after window creation

awah8-Jul-05 3:39

awah

8-Jul-05 3:39

hi, i am new in MFC so i would need detail explaination and preferbly some codes

here is the application initialization

/////////////////////////////////////////////////////////////////////////////<br />
CAsevApp theApp;<br />
// CAsevApp initialization<br />
<br />
BOOL CAsevApp::InitInstance()<br />
{<br />
	// Standard initialization<br />
	// If you are not using these features and wish to reduce the size<br />
	//  of your final executable, you should remove from the following<br />
	//  the specific initialization routines you do not need.<br />
	RECT rec;<br />
	rec.bottom=100;<br />
	rec.left = 100;<br />
	rec.right = 100;<br />
	rec.top = 100;<br />
<br />
	main_window *m_pMainWnd = new main_window;<br />
	m_pMainWnd->Create(<br />
		"myWindowClass",<br />
		"title",<br />
		WS_OVERLAPPEDWINDOW,<br />
		rec,  CWnd::GetDesktopWindow(),0,0);<br />
return TRUE;

main_window is a derived class from CWnd, no extra stuff has been added

here i am trying to create a simple window with the "create" command
or more specifically, CWnd::Create command
what happens is that the program terminates immediately

i was expecting an empty movable/resizable window with the titlebar "title" to appear and stay there

is there something i did wrong?

please assist

Re: CWnd::Create -> program terminates immediately after window creation

David Crow8-Jul-05 4:23

David Crow

8-Jul-05 4:23

Any reason why you are doing it this (hard) way rather than having AppWizard create an SDI/MDI application for you sans Doc/View support?

"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown

Re: CWnd::Create -> program terminates immediately after window creation

Alexander ^M.,8-Jul-05 7:12

Alexander ^M.,

8-Jul-05 7:12

You need a modal loop to prevent the app from exiting!
The code you are using creates a window and then exits the main routine.
If you really want to create the window like this you have to call m_pMainWnd->RunModalLoop() after creating the window.

Don't try it, just do it! Wink | ;-)

Re: CWnd::Create -> program terminates immediately after window creation

ThatsAlok8-Jul-05 20:31

ThatsAlok

8-Jul-05 20:31

awah wrote:
is there something i did wrong?

Yeap, there is no Message Loop for that Window Running!

"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow

cheers,
Alok Gupta
VC Forum Q&A :- I/ IV

How to capure mouse move with child window overlapping ?

ldaoust8-Jul-05 3:17

ldaoust

8-Jul-05 3:17

Hi,

I have a window that has a some drawing in it and I have this child window that I would use to display information where the mouse is on the drawing.

How do I capture mouse movement in the chart window even when the mouse moves over the child window ?

I added a handler for WM_MOUSEMOVE to the chart window but when I pass over the child window I don't receive any WM_MOUSEMOVE messages, just when I am over the chart window. I need to get messages also when I am over that child window.

I know I could use GetCapture(), but I don't want to click the chart to initiate a GetCapture(), so if I use GetCapture() on that chart window, what would be the best way to know when to call release capture, in other words how do i know, for certain, that the mouse has left the chart window ?

thanks,
Louis.

Re: How to capure mouse move with child window overlapping ?

Manfred Staiger8-Jul-05 3:38

Manfred Staiger

8-Jul-05 3:38

From MSDN:

CWnd::SetCapture
Causes all subsequent mouse input to be sent to the current CWnd object regardless of the position of the cursor.
When CWnd no longer requires all mouse input, the application should call theReleaseCapture function so that other windows can receive mouse input.

I think that is what you want to do.

MS

Re: How to capure mouse move with child window overlapping ?

ldaoust8-Jul-05 4:07

ldaoust

8-Jul-05 4:07

Ok, I tried the SetCapture() and it works fine but I have a problem with the child window that I use to display information. This child window is moveable, but when SetCapture() is called for the chart window I cannot move the child window anymore (not receiving any messages)...I guess I could check with a hit test if the cursor is on the title bar of the child window...but this seems to be becoming a lot of work...is there another way ?

thanks for your help I am half way there.
Louis

Re: How to capure mouse move with child window overlapping ?

Manfred Staiger8-Jul-05 4:29

Manfred Staiger

8-Jul-05 4:29

You should also be able to trap these messages with PreTranslateMessge.
You need to add the handler for PreTranslateMessage (class wizzard). There you can "look" at the mouse messages and see for which window they are. Don' forget to pass them on to their destination.

MS

Re: How to capure mouse move with child window overlapping ?

ldaoust8-Jul-05 6:09

ldaoust

8-Jul-05 6:09

Good idea.

I added the handler seems to be working but again when mouse is in child window I dont receive messages. I don't get it, this child (chart info window) is just a child like the chart control.

Here's exactly what I have and did:
- A dialog that I use for a graph window.
- This dialog contains controls and one of those controls is a CStatic derived class that act as a chart control. There is nothing special about the control in how it handles messages except for drawing.
- At runtime I create a new dialog that is child of this dialog. This child dialog is the chart info window. To me it should be the same as another control in the dialog. It does nothing special, just contains a static control in which I display text. It has a title bar so I can move it around.
- I added a PreTranslateMessage handler to the main dialog and check for the WM_MOUSEMOVE message. If the point lies in the client rectangle of the chart control I display text in the chart info window (static control on that child dialog).

So far it works, just that when the mouse is over the chart info window, the main dialog does not receive any WM_MOUSEMOVE in PreTranslateMessage. I really don't understand why I receive message when I am over the chart control in the main dialog but not in the chart info window that is also a child of the main dialog. ??

I hope you get the 'picture', maybe a screenshot of the layout would help ? If so, how do I add an image to a post ?

thanks for all your help,
Louis.

Re: How to capure mouse move with child window overlapping ?

ldaoust8-Jul-05 6:32

ldaoust

8-Jul-05 6:32

Seems I found the problem.

There is a difference in using a dialog as a child of another dialog then using a basic control. What I did is that I substituted the chart info window (child dialog) for a CStatic control and now it works. Just that I don't have a title bar to move the control around...I should be able to find a way move it by clicking anywhere on it.

I beleive there must be a way to make a child dialog work as a basic control...I guess there is a message handler in the dialog that consumes the messages and are not relayed to the parent.

Louis.

Re: How to capure mouse move with child window overlapping ?

John R. Shaw8-Jul-05 17:30

John R. Shaw

8-Jul-05 17:30

I don't know if this will help. But in this entire thread, no one mentioned that a control is another window and only the window over which the mouse is moving gets the WM_MOUSEMOVE messages (not its parents).

You don't want to capture the mouse in your main window, because then your child windows will not receive mouse message (they will all go to your main window).

If you need to keep track of the cursor position, even when the mouse cursor is over a child window. Then you should start a timer in you main window (in this case your dialog window) and call GetCursorPos to get the screen coordinates of the cursor. Then there is an API function some where (I forgot the name of it), that can be used to get the handle of a window given the screen coordinates, that you need to call to determine which window you are over. If you need to display the coordinates, then you'll probably need to convert the screen coordinates to the local client coordinates.

INTP
"The more help VB provides VB programmers, the more miserable your life as a C++ programmer becomes."
Andrew W. Troelsen

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