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This is the expected behavior.
The MDI Parent has a control on it, called the MDIClient, that sits behind all other controls on the form. All MDI Child windows are rendered by the MDIClient control. Any controls you put on the MDI Parent form will sits "in front of" the MDIClient control.
It's possible to bring the MDIClient control to the front, but when you do this, it will cover the PictureBox control. You won't be able to see the picture you put in there.
The MDIClient control does have a BackgroundImage property, so you can setup a picture on it.
You can find out how to get a handle on the MDIClient control here[^].
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Yes I even put in my message that I found out that this was the expected behavior. I also put that I already have a background image so I cant use that as a solution to my problem. I need a "workaround" for this. I take it there is no way you can think of to accomplish what I need to do??? Thank you for replying to my question tho. Im not trying to down your post or anything, it just didnt give me any information I didnt already know.
There has got to be a way to accomplish what I am trying to do. I am not advanced enough to figure it out tho. I am still pretty much a begginer at programming. I guess you could call me an "advanced-beginner". Not quite to the novice class yet... So please, all advanced programmers: HELP ME!!!!!
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I'm not entirely sure what you're trying to do. That's why you got the description you did.
But, if you're trying to show two images as the background of the MDIClient area, you need to combine them as a single bitmap and set the BackgroundImage of the MDIClient to that new image. There is no other alternative.
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I have a tooltip defined for a datagridview cell. It displays when I hover the mouse over the cell. I'd like however to update the contents of that tooltip when it displays. How can I best do that? Is there a tooltip display event? The mousehover event doesn't seem to really work in this regard.
Thanks
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I think there is show and/or popup event. Not sure though
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Or perhaps mousehover would work if I knew how to reset it once it fired once (without having to move the mouse outside of and then back into the DGV).
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If I get what you're talking about doing, there isn't an event like you're talking about.
What you'd have to do is handle the DGV's CellMouseHover and probably CellMouseLeave events to interrogate the cell the mouse is over and set the ToolTip's Text property as the mouse moves.
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OK, well that made the whole thing painfully obvious -- just set the tooltip on the cellmouseenter event. DOH!
Thanks
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You can make updatable tooltips by making use of the following steps using Javascript.
For the first time, On mouse over event you can create a "DIV" control using "createElement" method with the respective text. Then, you can update the content of the "DIV" element innertext on mouse out event(you can hide this "DIV").
While creating the control make the "Control ID" uniform across all the cells, so that you don't need to recreate the control every time.
If it's already there you can just make the display property to 'block' or else create the control newly.
Hope this helps you.
Regards,
Vengat P
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This won't work in a Windows Forms app, just web...
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I'm writing a little app to save the clipboard to a file and then mail a link to it to selected recipients. For the saved file to be accessible by the recipients, I verify that the parent folder is shared.
However, if the share is on a local drive, I have to convert the full path to something like:
DriveID:\SomePath1\SharedFolderName\SomePath2\FileName.ext
and then to:
\\HostDNSname\ShareName\SomePath2\FileName.ext
where ShareName is the provider name for:
DriveID:\SomePath1\SharedFolderName
and SharedFolderName is the 'deepest' level share - i.e., it accounts for the possibility of SomePath1 including higher level shared folders.
I'm using the Win32_LogicalDisk ManagementClass and Win32_Share ManagementClass to obtain the info I need, but have not found an easy way to do the path conversion.
Before I dig into the implementation, I thought I'd check to see whether anyone has attempted this and whether they found an easy way to do this.
Comments would be appreciated...
emilG
"Dealing with failure is easy: Work hard to improve.
Success is also easy to handle: You've solved the wrong
problem. Work hard to improve." - Alan Perlis
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What's so hard about removing the beginning of a string and replacing it with a workstation name?
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Nothing hard, once I have the string. For instance, if I have the following shares on my machine:
D:\ with a share name of "D$"
and:
D:\MyPrivateDownloads\Tools\ABCtool\ with a share name of "ABCdownload"
plus a bunch of other shares on the same drive, with the file stored in:
D:\MyPrivateDownloads\Tools\ABCtool\Docs\UserManual\UsingABCinfo.pdf
I want to send the following link:
\\myMachineName\ABCdownload\Docs\UserManual\UsingABCinfo.pdf
and not:
\\myMachineName\D$\MyPrivateDownloads\Tools\ABCtool\Docs\UserManual\UsingABCinfo.pdf
So, although it is not rocket science to accomplish this, I was wondering if there was an easy way of accomplishing it [via some framework class maybe].
emilG
"Dealing with failure is easy: Work hard to improve.
Success is also easy to handle: You've solved the wrong
problem. Work hard to improve." - Alan Perlis
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1. Dave is right on this. You're making this to difficult. Do something like:
replace("D:\MyPrivateDownloads\Tools\ABCtool\Docs\UserManual\UsingABCinfo.pdf","D:\MyPrivateDownloads\Tools", "\\" & environment.GetEnvironmentVariable("ComputerName"))
Keep it simple.
egottwald wrote: D:\ with a share name of "D$"
2. C$ and D$ are admin shares and shouldn't be used. If it were me, I'd disable them entirely because someone could just access all the dirs/files regardless of what you intended (with \\myMachineName\D$).
Any suggestions, ideas, or 'constructive criticism' are always welcome.
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1. You're making it too simple. The string replace is trivial when the strings are known. In an app, they are both dynamic, and what I'm ideally looking for is something like:
<br />
strSavedFileFullPath = GetSavedFileLocation() ' <<< This is not a problem<br />
If IsLocalShare(strSavedFileFullPath) Then ' <<< This is not a problem either<br />
strLinktoSend = ConvertFullPathToClickableLink(strSavedFileFullPath)<br />
End If<br />
I know how to code ConvertFullPathToClickableLink, but is there an API I can use instead?
2. I used D$ as an example...
emilG
"Dealing with failure is easy: Work hard to improve.
Success is also easy to handle: You've solved the wrong
problem. Work hard to improve." - Alan Perlis
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egottwald wrote: but is there an API I can use instead
Not in the .NET Framework, no.
Typically, I wouldn't be sharing stuff from individual users machines. They'd be forced to post stuff on a central temp drive, that I wipe out every night, and link to that.
In your situation, there are too many unknowns, so force one to be a known. In your example, it sounds like your code can either create a subfolder under a known share, or can create a share for a known folder. This is, to say the least, an administrative nightmare.
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I have two projects and both reference Microsoft Comm Control 6.0 (same GUID is being referenced in both). Both projects have CopyLocal = True and Isolated = false, but generate different sized AxInterop and Interop files? What would cause this when both projects are referencing the same .dll?
Project one generates:
AxInterop.MSCommLib.dll 11,776
Interop.MSCommLib.dll 15,360
Project two generates:
AxInterop.MSCommLib.dll 12,288
Interop.MSCommLib.dll 15,872
Any suggestions, ideas, or 'constructive criticism' are always welcome.
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Which version of VB.NET are you using??
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2005 Pro SP1.
Just to clarify a couple things for my own knowledge,
1. In theory, if you are creating interop projects on the same computer to the same .dll, they interop files should be the same right?
2. If #1 is true, you should be able to deploy the same 2 files for both projects (IE: a .net exe project is calling a .net .dll project, and both are using the interop'd vb6 comm control).
Thanks for any help.
Any suggestions, ideas, or 'constructive criticism' are always welcome.
modified on Tuesday, October 21, 2008 11:10 AM
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OK, since 2005 includes a Serial I/O class, why are you using the old MSCOMM control anyway??
I don't know why they're comming up with different interop's. In my, admittedly very limited, testing, I couldn't replicate the problem.
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Dave Kreskowiak wrote: OK, since 2005 includes a Serial I/O class, why are you using the old MSCOMM control anyway??
Management decision above my head. We have a considerable amount of custom code that controls many diff. types of machinery. Due to the size of the projects we are converting, the comm stuff must wait until everything is initially released.
Sigh..
I'll keep looking into the interop differences and post my results later.
Thanks for checking Dave.
Any suggestions, ideas, or 'constructive criticism' are always welcome.
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hi there , im quite new to vb , im using 2008 express .
i want to simply read this xml document and put just all the "artist" into a listbox. therefore just want to loop thought the xml and list the <artist>
i have worked out how to get just the first artist by this code but i want to have a list of them all .
<pre>Dim xmlfile = XDocument.Load("C:\ls\data\viddec.xml")
Dim imbd_code = xmlfile...<item>
msgbox(imbd_code.<artist>.Value)</pre>
heres an example xml...
<?xml version="1.0" encoding="utf-8"?>
<items Page="1" PageSize="100" PageCount="1" TotalRecordCount="9">
<item>
<artist> test1 </artist>
<album> album1 test </album>
</item>
<item>
<artist> test2 </artist>
<album> album2 test </album>
</item>
any help would be great ,i have looked on the net and followed some guides but i have yet found what i want.
cheers
luke
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try the following
Dim oDOm as new xmldocument
odom.load("c:\ls\data\fiddec.xml")
dim oxmlelem as xmlelement
dim l as new list(of string)
for each oxmlelem in odom.selectnodes("//item")
dim oxmlartist as xmlelement = oxmlelem.selectsinglenode("artist")
if oxmlartist isnot nothing then l.add(oxmlartist.innertext)
next
This is from memory so ...
Also note that the xmltags are case sensitive
Hope this helps
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You might want to have a look at some of the code here - http://forums.microsoft.com/MSDN/ShowPost.aspx?PostID=1759860&SiteID=1
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