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Hi, Thanks a lot for your help. I managed to fix the "
The user does not have the EXECUTE PROCEDURE access to SQLJ.REPLACE_JAR " I created a new question in the correct place. I visit the documentation and didn't manage to fix the signature error. Even I have tried the example of Teradata and still face the same error.
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If I pass the url=http/market/state/update,I need the output as MARKET_STATE_UPDATE but now I am getting MARKET _UPDATE.
please share your thoughts to help me to solve the issue
String[] tokens = requestUrl.getPath().split("/", -1);
for (String tokens1 : tokens) {
switch (tokens1)
case "market":
if (requestType.equals("put")) {
if (tokens.equals("state")) {
return RecordDto.EventTypeEnum.MARKET_STATE_UPDATE;
} else if (tokens.equals("chain")) {
return RecordDto.EventTypeEnum.MARKET_CHAIN_UPDATE;
} else {
return RecordDto.EventTypeEnum.MARKET_UPDATE;
}
} else if (requestType.equals("delete")) {
if (tokens.equals("chain")) {
return RecordDto.EventTypeEnum.MARKET_CHAIN_DELETE;
}
break;
Case "value":
if (requestType.equals("put")) {
if (tokens.equals("level")) {
return RecordDto.EventTypeEnum.Value_LEVEL_UPDATE;
} else if (tokens.equals("period")) {
return RecordDto.EventTypeEnum.Value_PERIOD_UPDATE;
} else {
return RecordDto.EventTypeEnum.VALUE_UPDATE;
}
} else if (requestType.equals("delete")) {
if (tokens.equals("period")) {
return RecordDto.EventTypeEnum.VALUE_PERIOD_DELETE;
}
}
break;
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I would highly encourage using the URL parameterization in whichever HTTP development framework you're using. That would simplify a lot of things.
- The HTTP request methods should not be checked in the method body itself. It makes very less sense. If you're going to run a logic based on the HTTP verb, create a separate handler for that verb. Most frameworks support that—Spring Boot, for example, does support HTTP verb-based routing.
- The URL itself can be created as a parameterized URL, then you can capture the values inside the parameters for the action.
You can create a request handler like,
@PutMapping("/http/{market}/{state}/{update}")
@ResponseBody
public RecordDto.EventTypeEnum putUpdate(
@PathVariable String market,
@PathVariable String state,
@PathVariable String update) {
if (state.equals("state") {
return RecordDto.EventTypeEnum.MARKET_STATE_UPDATE;
} else {
}
}
This way you leave a lot of processing and parsing to the framework itself. Read more about @PathVariable on Baeldung.
For a basic Java application, it might make sense to write the conditional blocks within the method body, but as your application scales, it becomes difficult to understand the flow of a program. That is why keep everything separated; that's one of the SOLID principles.
The sh*t I complain about
It's like there ain't a cloud in the sky and it's raining out - Eminem
~! Firewall !~
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Gostaria de saber como fazer para abrir um extrato bancario em pdf em uma tabela pelo java. Isso se faz através de alguma aplicação q faz a leitura desse pdf e joga para essa tabela?
Google Translate: I would like to know how to open a bank statement in pdf in a table using java. Is this done through some application that reads this pdf and plays to this table?
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This is an English language site, and we can only accept and answer questions in that language.
I have run this through Google Translate to produce a probably-good version, but you should check it and make sure it does say what you are actually asking.
Yes. You would need to read the PDF file into your Java app - this may help: How to Read and Write PDF file in Java - Studytonight[^]
Then extract the table info you need - we have no idea how the PDF file is organised, so that's going to be all your problem - and display it as normal.
Google Translate: Este é um site em inglês e só podemos aceitar e responder a perguntas nesse idioma.
Eu executei isso no Google Tradutor para produzir uma versão provavelmente boa, mas você deve verificar e certificar-se de que diz o que você está realmente perguntando.
sim. Você precisaria ler o arquivo PDF em seu aplicativo Java - isso pode ajudar: Como ler e gravar arquivo PDF em Java - Studytonight[^]
Em seguida, extraia as informações da tabela que você precisa - não temos ideia de como o arquivo PDF está organizado, então esse será todo o seu problema - e exiba-o normalmente.
"I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
"Common sense is so rare these days, it should be classified as a super power" - Random T-shirt
AntiTwitter: @DalekDave is now a follower!
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import java.io.File;
import java.io.IOException;
import org.apache.pdfbox.pdmodel.PDDocument;
import org.apache.pdfbox.text.PDFTextStripper;
public class NewClass {
public static void main(String[] args) throws IOException{
try {
// Creating file instance
File file = new File("test.pdf");
// Loading pdf file
PDDocument document = PDDocument.load(file);
PDFTextStripper pdfStripper = new PDFTextStripper();
// Fetching PDF document
String text = pdfStripper.getText(document);
System.out.println(text);
// Closing the document
document.close();
}catch(Exception e) {
System.out.println(e);
}
}
}
/PDDocument document = PDDocument.load(file);/ In this line there is an error in load, and I can't run the project
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Daniel Carvalho 2022 wrote: In this line there is an error in load,
And that error would be what? I suspect it has to do with the file's relative path (which defaults to current [i.e., "./test.pdf"] if none is provided), but only you know for sure.
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"You can easily judge the character of a man by how he treats those who can do nothing for him." - James D. Miles
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I've tried changing the path and it still has the same error. Is there any other way to perform the same function?
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As David said:
➡️ And that error would be what? ⬅️
It's no use repeatedly telling us you have "the same error" when you've never told us what the error is. 
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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Error?
FileNotFound
ClassNotFound
PdfFormatException
Full stack trace helps
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The URL of the site is:
https://www.lowes.com/pd/7-16-CAT-PS2-10-OSB-Sheathing-Application-as-4-x-8/50382768[^]
The information that I am trying to obtain is the price. Using Chrome's Inspect view, I was able to drill down to the price element in question. The Xpath of that element looks like:
/html/body/div[3]/section/div/div[7]/div[1]/div[2]/div[1]/span/div[1] I really wanted to see that in some "tree" form, so I walked the HTML backward from that element back to the top. That looks like:
<html>
<body>
<div id="app">
<section role="main" id="main" class="app__Container-PDP__sc-9tcy1n-0 bglOQr">
<div class="style__ProductDetailsWrapper-PDP__sc-4buzay-0 fwCYaB">
<div class="style__Wrapper-PDP__sc-1a0l1ro-1 hiRMxh product-info">
<div class="style__ProductDescDeskWrapper-PDP__sc-1a0l1ro-6 fpGRzR">
<div class="style__ProductTitleWrapper-PDP__sc-1a0l1ro-11 fUmbqY">
<div tabindex="0" class="styles__PriceWrapper-sc-1c3t51u-0 ZQLLV priceWrapper">
<span class="finalPrice">
<div class="sc-hGPBjI eomYbK">$30.65 </div>I was able to throw some Java code together (read: ugly) to drill down to that level but got stopped at the next-to-last DIV element.
...
Elements elements = element.getElementsByAttributeValue("class", "style__ProductTitleWrapper-PDP__sc-1a0l1ro-11 fUmbqY");This returns a 1-item collection as it should. If I then follow that with:
Element element = elements.get(0);
elements = element.getElementsByAttributeValue("class", "styles__PriceWrapper-sc-1c3t51u-0 ZQLLV priceWrapper");It returns an empty collection. I assume this is because no such class could be found. However I can plainly see that DIV element in the Inspect view.
I can get the sibling elements to the one in question. I even tried searching for getElementsByAttributeValue("tabindex", "0"), and while it correctly found 2 elements, neither are the one I want.
Any idea(s) as to what I'm missing (or not understanding)?
Thanks.
DC
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"You can easily judge the character of a man by how he treats those who can do nothing for him." - James D. Miles
modified 20-Jan-22 16:23pm.
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Did you try to skip the random in the middle?
Go straight for “class”, “finalPrice”
The extract the nested text node to skip the last div
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Make a program that takes n numbers and computes the sum of
positive numbers. If the entered number is 0, the program will
terminate
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Sorry, this site does not provide code to order. If you do not understand how to write a simple Java sample then take a look at Java Tutorials Learning Paths[^].
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There are many excellent books that you could use to learn Java. Alternatively, you could look at courses and training videos on places like Pluralsight, Udemy and so on.
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Use the link in my message above yours. It is a well presented tutorial which takes you from the basics right through to many of the advanced concepts.
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import java.io.*;
public class SumOfPositive{
public static void main(String args[])throws Exception{
int sum=0;
System.out.println("Enter how many you need to add");
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int n=br.readLine();
for(int i=0;i<n;i++)
{
if(a[i])="=0)
" system.exit(0);
="" if(a[i]="">0)
sum=sum+a[i];
}
System.out.println("Sum of positive numbers:"+sum);
}
}
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i am using apache tomcat and am having trouble connecting my external style sheet to my jsp page.
i have tried google,stack overflow and can't find a solution to my problem.
my repository URL:<a href="https://github.com/jonathanIckovich/divina-popina.git">GitHub - jonathanIckovich/divina-popina</a>[<a href="https://github.com/jonathanIckovich/divina-popina.git" target="_blank" title="New Window">^</a>]
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import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the size of the array");
int n = sc.nextInt();
int arr[]=new int[n];
System.out.println("Enter the elements of the array");
for(int i=0;i<n;i++)
{
arr[i]=sc.nextInt();
}
DivArray(arr,0,arr.length-1);
for(int z:arr)
{
System.out.print(z+" ");
}
}
static void DivArray(int arr[],int low,int high)
{
if(low<high)
{
int mid=(low+high)/2;
DivArray(arr,low,mid);
DivArray(arr,mid+1,high);
MergeSort(arr,low,mid,high);
}
}
static void MergeSort(int arr[],int low,int mid,int high)
{
int i = low;
int k = low;
int j = mid+1;
int dummy[]=new int[arr.length];
while(i<=mid && j<=high)
{
if(arr[i]<arr[j])
{
dummy[k]=arr[i];
k++;
i++;
}else{
dummy[k]=arr[j];
k++;
j++;
}
}
while(i<=mid)
{
dummy[k]=arr[i];
k++;
i++;
}
while(j<=high)
{
dummy[k]=arr[j];
k++;
j++;
}
for(int q=0;q<arr.length;q++)
{
arr[q]=dummy[q];
}
}
}
OUTPUT:
Enter the size of the array
8
Enter the elements of the array
9 8 7 6 5 4 3 2
0 0 0 0 0 0 0 0
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You need to use the debugger to find out exactly what is happening to your array in the DivArray and MergeSort methods.
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import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the size of the array");
int n = sc.nextInt();
int arr[]=new int[n];
System.out.println("Enter the elements of the array");
for(int i=0;i<n;i++)
{
arr[i]=sc.nextInt();
}
DivArray(arr,0,arr.length-1);
for(int z:arr)
{
System.out.print(z+" ");
}
}
static void DivArray(int arr[],int low,int high)
{
if(low<high)
{
int mid=(low+high)/2;
DivArray(arr,low,mid);
DivArray(arr,mid+1,high);
MergeSort(arr,low,mid,high);
}
}
static void MergeSort(int arr[],int low,int mid,int high)
{
int i = low;
int k = low;
int j = mid+1;
int dummy[]=new int[arr.length];
while(i<=mid && j<=high)
{
if(arr[i]<arr[j])
{
dummy[k]=arr[i];
k++;
i++;
}else{
dummy[k]=arr[j];
k++;
j++;
}
}
while(i<=mid)
{
dummy[k]=arr[i];
k++;
i++;
}
while(j<=high)
{
dummy[k]=arr[j];
k++;
j++;
}
for(int q=0;q<arr.length;q++)
{
arr[q]=dummy[q];
}
}
}
OUTPUT:
Enter the size of the array
8
Enter the elements of the array
9 8 7 6 5 4 3 2
0 0 0 0 0 0 0 0
modified 3-Dec-21 4:28am.
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Move the code the displays the sorted array out of the MergeSort method, and into your Main method, after the call to DivArray.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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I am trying to extract date from a String (Line), to do a Date conversion, but my String concatenation (#1) gives incorrect result.
Adding a blank ("") at the start (#2) gives the correct result.
Why is this? Where does the "105" come from?
System.out.println("Line= " + Line);
char ch1 = Line.charAt(0), ch2 = Line.charAt(1);
char ch4 = Line.charAt(3), ch5 = Line.charAt(4);
char ch7 = Line.charAt(6), ch8 = Line.charAt(7),
ch9 = Line.charAt(8), ch10 = Line.charAt(9) ;
System.out.println("Text date= " + ch1 + ch2 + '/' + ch4 + ch5 + '/' +
ch7+ ch8+ch9+ch10);
String sDate1= ch1 + ch2 + "/" + ch4 + ch5 + '/' +
ch7+ ch8+ch9+ch10;
System.out.println("Not correct: sDate1= " + sDate1);
String sDate2= "" + ch1 + ch2 + "/" + ch4 + ch5 + '/' +
ch7+ ch8+ch9+ch10;
System.out.println("Correct: sDate2= " + sDate2);
Output:
Line= 09/12/2021
Text date= 09/12/2021
Not correct: sDate1= 105/12/2021
Correct: sDate2= 09/12/2021
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It "thinks" you're doing "addition", then string concatenation in the first instance (0x30 + 0x39 == 105 == char(0) + char(9)); and all string concats in the second; due to the leading quote.
It was only in wine that he laid down no limit for himself, but he did not allow himself to be confused by it.
― Confucian Analects: Rules of Confucius about his food
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