JavaScript

Richard MacCutchan15-Jul-22 22:29

15-Jul-22 22:29

You need to show the code you have for people to help you. No one here is going to write your complete assignment.

User 1567076215-Jul-22 23:59

User 15670762

15-Jul-22 23:59

function colorSelector (colorCode) {

let randomNumber = Math.floor((Math.random() * 100));

if (randomNumber < 10) {
    console.log("green");
}

else if (randomNumber >= 10 && randomNumber < 19) {
    console.log("yellow");
}

else if (randomNumber > 19) {
    console.log("blue");
}


return (randomNumber);


}

console.log(colorCode);

This is how far I got. Im confused what should be inside the function and what should we outside. Im also not sure if im using the return operator the right way.

modified 29-Aug-22 21:01pm.

Richard MacCutchan16-Jul-22 0:09

16-Jul-22 0:09

Your code is quite confused, and confusing. You specify that the function takes an input parameter named colorCode, but you never refer to it in the function. Your if/else clauses include the variable condition which is never defined anywhere. Finally you return the randomNumber for no reason I can see.

- The function does not need an input parameter, unless you want to pass it a random number. Assuming yo do not, then generate the number as the first step.
- The if statements only need to be as follows
- 1: If the value is less than 10 set colorCode to "green"
- 2: Else If it is less than 50 set colorCode to "yellow" (we already know it is not less than 10)
- 3: Else set it to "blue" (it must be 50 or greater)
- return colorCode to the caller of the function.

modified 16-Jul-22 7:11am.

Eddy Vluggen16-Jul-22 4:53

Eddy Vluggen

16-Jul-22 4:53

So, you nearly there.

function colorSelector (colorCode) {

let randomNumber = Math.floor((Math.random() * 100));

if (randomNumber < 10) {
    console.log("green");
}

else if (randomNumber >= 10 && randomNumber < 19) {
    console.log("yellow");
}

else if (randomNumber > 19) {
    console.log("blue");
}


return (randomNumber);


}

console.log(colorSelector(50));

I got a warning that "colorCode" doesn't exist. And true, it doesn't. That makes it confusing, because there's two options. Let's forget them for a second. Try the code I gave you, vary the number. It writes to the console also.

Member 15708114 wrote:
I know that I have to use the Math.floor and Math.random to create a random number and the if and return operators but I think im messing up the order. Please help anyone.

You creating a random number inside the function. You want to "pass" it to the function as an argument.

So you don't see where on thing starts and the other ends? It's called "scope". Ask your teacher. Once clear, ask to step.

It executes one line, shows result in debug. That way you see how the computer "steps" through your instructions.

Bastard Programmer from Hell Suspicious | :suss:

"If you just follow the bacon Eddy, wherever it leads you, then you won't have to think about politics." -- Some Bell.

Richard MacCutchan16-Jul-22 5:18

16-Jul-22 5:18

JavaScript

else if (randomNumber >= 10 && randomNumber < 19) {
         ^^^^^^^^^^^^^^^^^^

We know it is >= 10 from the previous if statement.

JavaScript

else if (randomNumber > 19) {

And it this point it must be > 19, so all that is needed is a simple else clause.

Eddy Vluggen16-Jul-22 5:46

Eddy Vluggen

16-Jul-22 5:46

Richard MacCutchan wrote:
And it this point it must be > 19, so all that is needed is a simple else clause.

That's the advanced course. I somehow think his teacher might have escaped that.

It's a beginner.

Bastard Programmer from Hell Suspicious | :suss:

"If you just follow the bacon Eddy, wherever it leads you, then you won't have to think about politics." -- Some Bell.

Richard MacCutchan16-Jul-22 5:51

16-Jul-22 5:51

But that is nothing to do with programming, it is simple mathematical logic.

Eddy Vluggen16-Jul-22 6:00

Eddy Vluggen

16-Jul-22 6:00

Correct. It got to do with education.

Bastard Programmer from Hell Suspicious | :suss:

"If you just follow the bacon Eddy, wherever it leads you, then you won't have to think about politics." -- Some Bell.

extract value from json Object in Node JS

Gerry Schmitz16-Jul-22 6:49

Gerry Schmitz

16-Jul-22 6:49

There was no requirement for a "random number"; the requirement was for a function that accepts a number.

And that function could be tested any number of ways; usually with a "console app" that accepts a number as input from the user and then uses that number in that function, and displaying the result.

JavaScript

if ( n < 10 ) {
   // green
else if ( n <= 50 ) {
   // yellow.
} else {
   // blue.
}

"Before entering on an understanding, I have meditated for a long time, and have foreseen what might happen. It is not genius which reveals to me suddenly, secretly, what I have to say or to do in a circumstance unexpected by other people; it is reflection, it is meditation." - Napoleon I

janaswamy uday12-Jul-22 8:23

janaswamy uday

12-Jul-22 8:23

Hello,

I am having a JSON Object as below in Node JS editor:

{"replyType":"queryDataRqst","requestId":169,"errCode" ,"options" ,"ccuSec":1657531129,"ccuNanosec":257000000,"replyData":[["IncidentStatusLine","\"machineId\":1111,\"incidentTidx\":101016,\"helpTidx\":101017,\"componentTidx\":100100,\"type\":2,\"state\":2,\"priority\":10,\"args\":{\"userData\":[{\"_d\":858993459,\"stringTidxValue\" ,\"longValue\":-634515298,\"realValue\" .0,\"nullValue\" },\"_d\":286331153,\"stringTidxValue\" ,\"longValue\" ,\"realValue\" .0,\"nullValue\" },\"_d\":286331153,\"stringTidxValue\" ,\"longValue\" ,\"realValue\" .0,\"nullValue\" },\"_d\":286331153,\"stringTidxValue\" ,\"longValue\" ,\"realValue\" .0,\"nullValue\" },\"_d\":286331153,\"stringTidxValue\" ,\"longValue\" ,\"realValue\" .0,\"nullValue\" },\"_d\":286331153,\"stringTidxValue\" ,\"longValue\" ,\"realValue\" .0,\"nullValue\" }]},\"text\":\"\",\"sequencenum\":287,\"timestamp\":1657522757472000000,\"wintimestamp\":133019963574720000,\"hashval\":-492839581,\"hideable\":false}"]]}

Now I need extract the value from the above JSON String as below:

{"userData":[{"_d":858993459,"stringTidxValue" ,"longValue":-634515298,"realValue" .0,"nullValue" },"_d":286331153,"stringTidxValue" ,"longValue" ,"realValue" .0,"nullValue" },"_d":286331153,"stringTidxValue" ,"longValue" ,"realValue" .0,"nullValue" },"_d":286331153,"stringTidxValue" ,"longValue" ,"realValue" .0,"nullValue" },"_d":286331153,"stringTidxValue" ,"longValue" ,"realValue" .0,"nullValue" },"_d":286331153,"stringTidxValue" ,"longValue" ,"realValue" .0,"nullValue" }]}

How to get this value using Node JS.

Thanks,

Uday

Re: extract value from json Object in Node JS

Ben Code16-Aug-22 0:59

Ben Code

16-Aug-22 0:59

Valid JSON is required first. I edited the JSON to make it compliant.
Solution - right-click and choose 'Open link in new window'

modified 16-Aug-22 6:38am.

WebView2 - Send Script with a Value

Alan Burkhart5-Jul-22 10:28

Alan Burkhart

5-Jul-22 10:28

I'm using WebView2 to display data in my app. If I send a string literal it works fine. But if I send a value in a variable I get nothing.

This works:

wb.ExecuteScriptAsync("document.body.innerHTML=" & ChrW(39) & "HELLO" & ChrW(39))

This doesn't ("lStr" is my string variable):

wb.ExecuteScriptAsync("document.body.innerHTML=" & ChrW(39) & lStr & ChrW(39))

I assume I'm doing something wrong here. Any advice is appreciated.

Sometimes the true reward for completing a task is not the money, but instead the satisfaction of a job well done. But it's usually the money.

Richard Deeming7-Jul-22 3:19

Richard Deeming

7-Jul-22 3:19

That's going to depend on the content of your variable, which we can't see.

For example, if the variable contains a single quote or any newline characters, your script will end up with an "unterminated string literal" error.

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Alan Burkhart7-Jul-22 15:05

Alan Burkhart

7-Jul-22 15:05

Could possibly contain quotes but no newline chars. I was trying to give my old spell checker a facelift. I wanted to use the WebView2 for the error text ("Not In Dictionary"). It's one line from the text editor with the error highlighted. So I'd need to send it the error start/end positions plus tell it to scroll to that position. All easily done if I could figure out how to send it a value in a variable.

Sometimes the true reward for completing a task is not the money, but instead the satisfaction of a job well done. But it's usually the money.

Richard Deeming7-Jul-22 22:42

Richard Deeming

7-Jul-22 22:42

As I said, you'll need to ensure the value is properly encoded.

Assuming you're running .NET Framework 4.7.2 or later, .NET Core, or .NET 5+, then you can use the System.Text.Json package[^] to encode the string:

VB.NET

wb.ExecuteScriptAsync("document.body.innerHTML=" & System.Text.Json.JsonSerializer.Serialize(lStr))

For older frameworks, use the Json.NET[^] package.

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer