ASP.NET

5-Jan-07 5:35

Hi
C# / IIS.

I have a user defined control (derived from HtmlInputButton) which registers client side javascript when instantiated. If this control is present when the page is created, the javascript is registered. Nothing impressive there.

but...and ain't there always....

I want to create this control on the fly as part of a partial screen udpate using ajaxy/atlas type methods. The control is created, displayed etc, but the javascript isn't written out. I know why, as the page isn't being redrawn, and only the <div> is affected by some deeply hidden XMlHttpRequest object thingy, but that isn't much use to me.

So, the question is, can I register Javascript after the page is created, and if so, how? I tried creating the button, hiding it until needed, but the button params, and bits of the generated Javascript will only be known at runtime, so this isn't really an option. Any help much appreciated.

Cheers

Not Active5-Jan-07 6:10

Not Active

5-Jan-07 6:10

The first thought that comes to mind is why not register the script whether the control is on the page or not. Not optimal, and I probably don't understand your situation, but the script would be there when needed, no hassles about how to load it.

only two letters away from being an asset

Malcolm Smart5-Jan-07 12:11

5-Jan-07 12:11

I tried that, but the script is created based on other input on the screen. I don't know 'exactly' what the script will be until runtime, ie the user makes a few selections, and then this button appears.

minhpc_bk6-Jan-07 4:50

minhpc_bk

6-Jan-07 4:50

In this case, you don't use the RegisterStartupScript method to register your dynamic script as it requires a postback. You may consider emitting the script along with the output html markup of your custom control, I mean in your control you can override the RenderXXX methods to emit the dynamic script with the script element to the writer, and as a result the dynamic script is also appended to the document at runtime like the dynamic control.

Malcolm Smart7-Jan-07 9:11

7-Jan-07 9:11

Sounds good - I'll give that a try.

Cheers

Malcolm Smart8-Jan-07 1:42

ASP.NET cannot read GAC even though has full access

8-Jan-07 1:42

Solution (simplified)

<br />
namespace MS_Test/// <br />
{<br />
public class myButton : HtmlInputButton<br />
{<br />
	public myButton( string t)<br />
	{<br />
        Value = t;<br />
        Attributes.Add("onclick", "testMe()");<br />
	}<br />
<br />
    protected override void Render(HtmlTextWriter writer)<br />
    {<br />
        Page.ClientScript.RegisterStartupScript(this.GetType(), "tt", "function testMe(){alert('tested');}", true);<br />
        base.Render(writer);<br />
    }<br />
}<br />
}<br />

Regards

Angel
*********************************************

Ed.Poore5-Jan-07 5:32

Re: ASP.NET cannot read GAC even though has full access

5-Jan-07 5:32

I've been trying to setup IIS & ASP.NET 2 onto a Windows 2000 SP4 box. The application it's supposed to be running has been written on my XP laptop and works fine but now it has to run on this machine.

IIS was already installed on it (with .NET 1 and 1.1), I installed .NET 2 and copied across the necessary files (tested and it compiles fine with MSBuild on the 2000 machine). When you try and view the page in IE a "Service Unavailable" message is displayed telling you to look at the log. There are three entries, the most pertinent being:

Failed to execute the request because the ASP.NET process identity does not have read permissions to the global assembly cache.
Error: 0x80070005 Access is denied.

There is also a warning message just before this one saying that it was unable to load System.Web because access was denied.

I've googled around and checked through all the knowledge base articles about permissions etc to the point where the ASPNET user on the server has full control to the required directories. As do the two other IIS accounts. Also tried aspnet_regiis -i and restarting IIS to no avail.

Does anybody have any ideas, without having to reinstall everything preferably because I have access to the server through VNC (and admin priviledges on it) so if preferable I don't want to reboot as I won't be able to log in again Roll eyes | :rolleyes:

ed^nrgc5-Jan-07 6:47

ed^nrgc

5-Jan-07 6:47

Just a shot, try :

aspnet_regiis -ga domain\processusername

Re: ASP.NET cannot read GAC even though has full access

Ed.Poore5-Jan-07 7:29

Re: ASP.NET cannot read GAC even though has full access

5-Jan-07 7:29

Nada

Ed.Poore6-Jan-07 8:05

Re: ASP.NET cannot read GAC even though has full access

6-Jan-07 8:05

Just thought I'd mention that the error message reported by ASP.NET is complete & utter b*****cks, it couldn't get permission to the application directory, not the GAC. Mad | :mad:

I have no idea what I just said. But my intentions were sincere.

Ed.Poore6-Jan-07 8:04

6-Jan-07 8:04

Fixed - Permissions on app directory D'Oh! | :doh:

I have no idea what I just said. But my intentions were sincere.

table cell backcolor

aransiola5-Jan-07 5:31

aransiola

5-Jan-07 5:31

how do i cange the back color of a table cell? I want to backcolor a particular cell

t.aransiola

Malcolm Smart5-Jan-07 5:40

5-Jan-07 5:40

TableCell myRedCell = new TableCell();
myRedCell.BackColor = System.Drawing.Color.Red;

or if the cell is already present

myTable.myRows[thisRow].Cells[thisCol].BackColor = System.Drawing.Color.Red;

where thisRow and thisCol are indexes into the table

Regards

Angel
*********************************************

RichardGrimmer5-Jan-07 5:51

RichardGrimmer

5-Jan-07 5:51

document.getElementById ('myTDid').style.background-color=#000000

"Now I guess I'll sit back and watch people misinterpret what I just said......"
Christian Graus At The Soapbox

aransiola5-Jan-07 6:03

aransiola

5-Jan-07 6:03

where do i put all these codes?
how do i know the cell reference to apply this code
remeber i am using a table to do a page layou. I just want to color some of the cells

t.aransiola

Malcolm Smart5-Jan-07 12:14

5-Jan-07 12:14

Are you doing this server side or client side. Post your code so we can see what you have tried already.