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The program doesn't print the common but instead the initialized value which is intended to increment as coded in the program.

And i think the problem lies in the while loop.

it would be appreciated if the following code is corrected instead of writing totally different code.

What I have tried:

#include <conio.h>
#include <stdio.h>

int main(){
	int a, b, i, j;
	int total_a=0, total_b=0;
	printf("Enter your integers: \n");
	scanf(" %d%d", &a, &b);
	for(i=1, j=1; i<=a,j<=b; i++,j++){
			total_a = total_a*10 + i;
			total_b = total_b*10 + j;
	/*printf(" %d %d", total_a, total_b);
	int total=0;
	printf(" %d", total);*/

	int rem_a, rem_b, total =0;

		rem_a = total_a%10;
			rem_b =total_b%10;
				total = total*10 + rem_a;
	printf(" %d", total);
	return 0;
Updated 7-Oct-17 21:30pm

1 solution

Um. You need to think some more about this: your code doesn't do what you think it will.
for(i=1, j=1; i<=a,j<=b; i++,j++){

Inside this loop, i and j will always have the same value; they will both start at one, then they will both be two, and so on. I'm not sure when they will stop, because I've not seen a condition with a comma in it before and I doubt it will compile - I'm on a tablet and have no C compiler at the moment s I can't check, but I don't think it's valid C code.

Probably, you need a nested pair of loops, rather than a single loop...
Share this answer
Richard MacCutchan 8-Oct-17 3:14am    
Just tried that and it works fine. The loop continues until the second expression (j<=b) is true. Which may, or may not, be what the programmer wants.
Tarun Jha 8-Oct-17 3:29am    
yes that's the problem, the while loop

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