Create multiple files with file object

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code that should create multiple files is

package FileSystem;

import java.io.File;
import java.io.IOException;

public class CreateFiles
{
    public static void main( String[] args ) throws IOException
    {	
        try
        {
        String[] Names = new String[20]; 
        Names[0] = "Android";
        Names[1] = "java";
        Names[2] = "computerscience";
        Names[3] = "satellite";
        Names[4] = "communication";
        Names[5] = "navigator";
        Names[6] = "science";
        Names[7] = "a";
        Names[8] = "b";
        Names[9] = "c";
        Names[10] = "d";
        Names[11] = "e";
        Names[12] = "f";
        Names[13] = "g";
        Names[14] = "h";
        Names[15] = "i";
        Names[16] = "j";
        Names[17] = "l";
        Names[18] = "m";
        Names[19] = "n";
        
        for(int j = 0; j<Names.length; j++)
        {
            File file = new File("F:\\" + Names + ".txt");                        	                    
        }
        }
        catch(Exception e)            
        {
            e.printStackTrace();
        }    
        finally
        {
        }
    }
}

there is no error message but the files are not created, similar code for single file works fine which is :

import java.io.File;
import java.io.IOException;

public class CreatesFile 
{
    public static void main( String[] args )
    {	
    	try {
    		 
	      File file = new File("c:\\newfile.txt");
	      
	      if (file.createNewFile()){
	        System.out.println("File is created!");
	      }else{
	        System.out.println("File already exists.");
	      }
	      
    	} catch (IOException e) {
	      e.printStackTrace();
	}
    }
}

the assignment is to create multiple files with different names

What I have tried:

changed code several times and searched

Posted 5-May-18 7:37am

four systems

Updated 5-May-18 7:54am

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Wendelius · Accepted Answer · 2018-05-05T07:55:00

Solution 1

Have a look at the file creation

Java

File file = new File("F:\\" + Names + ".txt");

You're referring to the array itself, not to an individual member. So you should use your counter variable j to specify the index from the array

Posted 5-May-18 7:55am

Wendelius

Comments

four systems 6-May-18 11:42am

File file = new File("F:\\" + j + ".txt"); is this is what you suggest, did that still does not create files, however found another way with

public class ForFilesWriter
{

public static void main(String[] args) throws IOException
{
BufferedWriter writer = null;
for(int i=1 ; i<=5 ; i++){
String fileName = "name" + i + ".txt";
PrintWriter printer = new PrintWriter(fileName, "UTF-8");
writer.write("Java is object oriented");
writer.close();
}}}

now would want to create files with names as the array has

public class ForFilesWriter
{

public static void main(String[] args) throws IOException
{
BufferedWriter writer = null;
String[] Names = new String[5];
Names[0] = "Android";
Names[1] = "java";
Names[2] = "computerscience";
Names[3] = "satellite";
Names[4] = "communication";
for(int i=1 ; i<=Names.length ; i++){
String fileName = "name" + i + ".html";
PrintWriter printer = new PrintWriter(fileName, "UTF-8");
printer.write("Java is object oriented");
writer.write("Java is object oriented");
writer.close();
}}}

Wendelius 6-May-18 13:51pm

No, that's not what I suggested.

You already use indexes when adding strings to the array. You use the individual values the same way.

Try

File file = new File("F:\\" + Names[j] + ".txt");

four systems 6-May-18 14:05pm

import java.io.File;
import java.io.IOException;

public class CreateFiles
{
public static void main( String[] args ) throws IOException
{
try
{
String[] Names = new String[20];
Names[0] = "Android";
Names[1] = "java";
Names[2] = "computerscience";
Names[3] = "satellite";
Names[4] = "communication";
Names[5] = "navigator";
Names[6] = "science";
Names[7] = "a";
Names[8] = "b";
Names[9] = "c";
Names[10] = "d";
Names[11] = "e";
Names[12] = "f";
Names[13] = "g";
Names[14] = "h";
Names[15] = "i";
Names[16] = "j";
Names[17] = "l";
Names[18] = "m";
Names[19] = "n";

for(int j = 0; j<Names.length; j++)
{
File file = new File("F:\\" + Names[j] + ".txt");
}
}
catch(Exception e)
{
e.printStackTrace();
}
finally
{
}
}
}
"the program runs but no files are created and there is no esception"

Wendelius 6-May-18 14:10pm

You still have to call the createNewFile method like you did in your example in the post.

four systems 6-May-18 14:25pm

wow, the files are created thanks

Wendelius 6-May-18 14:27pm

You're welcome :)