Ajax does not execute other page javascript

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I been researching for a long time and i'm so confused I read that you have to use the eval() function so plain ajax can recognize and execute the JavaScript on the other page I read thru a lot of sites but there is rarely no info on this or no examples that makes sense to me so can any one add the right code to my code to get this to work. I'm a visual learner.

index.php

HTML

<script>
var xhr= new XMLHttpRequest();
xhr.onreadystatechange= function(){
    if(xhr.readyState === 4){
        document.getElementById('ajax').innerHTML= xhr.responseText;
    }
};
xhr.open('POST','x.php');

function startAjax(){
    xhr.send();
document.getElementById('hide_button').style.display= 'none';
    }
    </script>
    <body>
    <button id='hide_button' onclick='startAjax()'>Start</button>
    <div id='ajax'></div>
    </body>

x.php

HTML

<script>
alert('js is executed');
</script>

<h1>Radom text</h1>

What I have tried:

I keep asking on many sites but nobody wants to help me out it's like they don't know how to do this or They don't modify my code to show how this can be done. The code works it's just not executing the js on the other page call x.php.

Posted 5-Jan-18 12:30pm

Member 13605567

Updated 5-Jan-18 15:10pm

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Karthik_Mahalingam · Answer 1 · 2018-01-05T15:10:00

refer this
Page1

<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
    <script>
        var xhr = new XMLHttpRequest();
        xhr.onreadystatechange = function () {
            if (xhr.readyState === 4) {
                var response = xhr.responseText; 
                document.getElementById('ajax').innerHTML = response;
                setTimeout(function () {
                    var script = document.getElementById('ajax').getElementsByTagName('script')[0];
                    if (script) {
                        var js = script.innerText;
                        eval(js);
                    } 
                }, 100)
                
            }
        };
        xhr.open('get', 'htmlpage2.html');

        function startAjax() {
            xhr.send();
            document.getElementById('hide_button').style.display = 'none';
        }
    </script>
</head>
<body>
    <button id='hide_button' onclick='startAjax()'>Start</button>
    <div id='ajax'></div>
</body>


</html>

Page2

<script>
    alert('js is executed');
</script>

<h1>Radom text</h1>