How do I convert char * to char array or structure variable?

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In my VC++ code,

I want to move value to another variables like as:

char* buf ="12345";

char logbuffer[1024];

strcpy(logbuffer, buf);

struct xx{
int a;
char b[1024];
}

xx yy;
memcpy(&yy.b, logbuffer, strlen(logbuffer));

I guess this is right.

but

if the logbuffer and yy are array like this;

char logbuffer[2][1024];

xx yy[2];

and if I try to move the value of buf to those variables like this:

strcpy(logbuffer[1], buf) and, or

memcpy(&yy[1].b, logbuffer[1], strlen(logbuffer[1]));

make compile error to say ambiguous sentense....

I don't what is main problem of this.

Please let me know the answer and correct method.

Thank you in advance.

What I have tried:

1 more days wasted of this problem.

Posted 10-Jun-17 4:20am

Member 12330615

Updated 10-Jun-17 5:38am

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Comments

Michael Haephrati 10-Jun-17 10:35am

The question is so unclear in terms of its English that I had to read it 5 times and yet I don't understand it at all. In my answer I gave a generic explanation but I can't comment on your source code itself because it isn't clear, where does it start and where does it end. What didn't work and what did?

2 solutions

Solution 2

Try this:

C++

char* buf = "12345";
char logbuffer[1024];

struct xx {
    int a;
    char b[1024];
};
xx yy;

strcpy(logbuffer, buf);
memcpy(yy.b, logbuffer, strlen(logbuffer)); // do not use & on yy

char logbufferb[2][1024];
xx yyb[2];

strcpy(&logbufferb[1][0], buf);  // do use & on logbufferb[1]

memcpy(yyb[1].b, &logbufferb[1][0], strlen(&logbufferb[1][0])); // see above comments

Note the above comments with respect to the addressof operator (&). Also note that using memcpy does not null terminate the strings, so you may have problems with it, always use strcpy.

Posted 10-Jun-17 5:38am

Richard MacCutchan

Updated 10-Jun-17 5:42am

v2

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This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Michael Haephrati · Accepted Answer · 2017-06-10T04:33:00

Solution 1

Don't use memcpy.
To copy one string to another, use strcpy().
strcpy received a pointer to each array of characters, or to be specific, to the first character in a NULL terminated array.

Posted 10-Jun-17 4:33am

Michael Haephrati

How do I convert char * to char array or structure variable?

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How do I convert char * to char array or structure variable?

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