Vector string into int... But utilizing at.(I)?

Question

1.00/5 (1 vote)

See more:

Hello,

I am somewhat familiar with converting using atoi in regards to a string to int:

C#

r.r= atoi(variable.c_str());

But how can I use this in conjuction with .at(i)?

If it matters, the string is a vector.

What I have tried:

C++

for (i = 1; i <= stringVariable.size; i++) {
		

MemberFunction(MemberFunction(atoi(stringVariable.at(i)), variable, variable);

}

Posted 6-Dec-16 16:59pm

Fence5

Updated 6-Dec-16 21:00pm

SoMad

v2

Add a Solution

Comments

Philippe Mori 7-Dec-16 10:32am

Write real code in your example.

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

User 59241 · Answer 1 · 2016-12-06T17:58:00

Solution 1

To utilise at(n) with atoi() use it thus:

C++

std::vector<std::string> v;

v.push_back("2222");

int i = atoi(v.at(0).c_str());

Posted 6-Dec-16 17:58pm

User 59241

Comments

KarstenK 7-Dec-16 3:13am

the solution is correct, but problematic in complex scenarios like some error handling.

CPallini · Answer 2 · 2016-12-06T21:00:00

Solution 2

There is a C++ way to do that, try:

C++

#include <iostream>
#include <sstream>
#include <vector>
using namespace std;

int main()
{
  vector < string > v{ "10", "20", "30" };

  for (const auto & x : v)
  {
    istringstream iss(x);
    int n;
    iss >> n;
    cout << n << endl;
  }
}

Posted 6-Dec-16 21:00pm

CPallini

v2

Comments

KarstenK 7-Dec-16 3:10am

Nice and funny ;-)

CPallini 7-Dec-16 3:16am

Thanks.