The name pet does not exists in the current context

Question

1.00/5 (2 votes)

See more:

When i run this code all i get is

C#

the name pet does not exists in the current context

and i am following this tutorial s[^] step by step not sure what is going on .

using System;

class Program
{
    enum PetType
    {
        None,
        Cat = 1,
        Dog = 2
    }

    static void Main()
    {
        // A.
        // Possible user input:
        string value = "Dogfff";

        // B.
        // Try to convert the string to an enum:



        try { PetType pet = (PetType)Enum.Parse(typeof(PetType), value); }

        catch (Exception ex)
        {

            Console.WriteLine(ex.Message);


            pet = PetType.None;
        }

        // C.
        // See if the conversion succeeded:
        if (pet == PetType.Dog)
        {
            Console.WriteLine("Equals dog.");
        }
    }
}

What I have tried:

************************************************
*
*
*******************************************************************************************************************

Posted 6-Oct-16 14:34pm

forte74

Updated 6-Oct-16 21:37pm

Add a Solution

Comments

[no name] 6-Oct-16 20:37pm

You need to read a basic programming book on variable scope. You have declared "pet" in the try block scope and you are trying to use it outside of the try block. pet is out of scope.

[no name] 6-Oct-16 23:46pm

"and i am following this tutorial s[^] step by step not sure what is going on ."
No you aren't. You changed the code and surprise surprise it doesn't work. You even know what you changed and the error message confirms it. Stick to the tutorial until you know what you are doing.

forte74 7-Oct-16 14:24pm

this reply doesnt help much anyways... if you can be a little bit more clearer it would help

[no name] 7-Oct-16 17:54pm

The code you show in your question is not the code in the example given in your link. The code in the link works and the differences introduced by you do not. I'm not sure how much clearer that can be put.

The Praveen Singh 7-Oct-16 2:44am

Declare pettype outside try block

Suvendu Shekhar Giri 7-Oct-16 2:47am

That's because you are trying to access pet outside of it's scope. You have declared it inside the try block and trying to access it outside it. What you can do is to declare it outside the try block so that it will be accessible globally within rest of your program. Something like following should help-

PetType pet;
try { pet = (PetType)Enum.Parse(typeof(PetType), value); }
catch (Exception ex)
{
    Console.WriteLine(ex.Message);
    pet = PetType.None;
}
// C.
// See if the conversion succeeded:
if (pet == PetType.Dog)
{
     Console.WriteLine("Equals dog.");
}

Hope, it helps :)

forte74 7-Oct-16 14:25pm

how would i go about declaring pet outside the try block... and what should i put in the try block then

Suvendu Shekhar Giri 7-Oct-16 15:28pm

Try the example I have shared

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Answer 1 · 2016-10-06T21:37:00

Solution 1

As Suvendu Shekhar Giri already pointed out, your PetType instance, namely pet is bad scoped: it is accessible just inside the try block.
You have to declare it before the try block and the instantiate it inside the try block itself.

C#

PetType pet;
try
{
   pet = ...

Please see: Variable and Method Scope in Microsoft .NET[^].

[update]
Fixed, thanks to Richard.
[/update]

Posted 6-Oct-16 21:37pm

CPallini

Updated 7-Oct-16 0:34am

v3

Comments

Richard MacCutchan 7-Oct-16 6:21am

Double declaration!

CPallini 7-Oct-16 6:34am

OOOOOOOOOOOOPS!
Thank you.