how to display a button inside grid view

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Hi
Thank you for Reply.

We are using Gridview in that i have one button and one text box when ever we click button that text must be visible how to do it using javascript or jquery.

Thanks & Regards
Lakshman

Posted 27-Jan-16 22:25pm

Member 9671482

Updated 2-Feb-16 22:17pm

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aarif moh shaikh 28-Jan-16 5:06am

<asp:GridView ID="gv" runat="server">
<columns>
<asp:TemplateField>
<itemtemplat>
<asp:Button ID="btnms" runat="server">
</itemtemplate>

</columns>

Manoj Sawant 28-Jan-16 5:10am

what did you try

aarif moh shaikh 3-Feb-16 4:32am

what have you try?
without datasource, we can't display any internal control in gridview.

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Anisuzzaman Sumon · Answer 1 · 2016-01-31T00:51:00

You can add button and textbox in the following manner so that when click on button textbox will be shown:

ASP

<asp:content id="BodyContent" contentplaceholderid="MainContent" runat="server" xmlns:asp="#unknown">

    <div class="jumbotron">

                <asp:gridview autogeneratecolumns="false" id="gdv1" runat="server">
            <columns>
                <asp:boundfield datafield="ID" />
                <asp:boundfield datafield="FirstName" />
                <asp:boundfield datafield="LastName" />
                <asp:templatefield>
                    <itemtemplate>
                        <input type="text" id="<%#Eval("ID") %>" hidden="hidden" />
                    </itemtemplate>
                </asp:templatefield>
                <asp:templatefield>
                  <itemtemplate>
                      <input type="button"  value="show" onclick="Show(this)"  />
                  </itemtemplate>
                </asp:templatefield>
            </columns>

        </asp:gridview>

            
        
    </div>

  
 
<script type="text/javascript">
    function Show(e) {
      
        $row = $(e).parent().siblings("").find('input');

        $row.show();


    }
</script>

</asp:content>