how to convert '/' to string in datatable

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C#

DataRow dr = dt.NewRow();
dr["id"] = i;
dr["Name"] = "Name" + i.ToString();
dr["Branch"] = Branches[brnc.Next(0, 3)];
dr["Age"] = ag.Next(17, 22);
dr["SocialMarks"] = marks1.Next(50, 100);
dr["MathsMarks"] = marks2.Next(50, 100);
dr["ScienceMarks"] = marks3.Next(50, 100);
dr["TotalMarks"] = dr["socialmarks"].ToString() + dr["MathsMarks"].ToString() + dr["ScienceMarks"].ToString();
dr["AverageMarks"] =//here totalmarks/3.0..that convert to string 
dt.Rows.Add(dr);

Posted 27-Dec-15 22:15pm

Member 12185899

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Rajesh waran 28-Dec-15 4:28am

try this,
dr["AverageMarks"] =(float.Parse(dr["TotalMarks"].ToString())/3).ToString();

Member 12185899 28-Dec-15 4:53am

yeah,Thanks Its working ...Iam getting Problem on Adding Marks ..

Rajesh waran 28-Dec-15 5:00am

Simple, then use the parse for three columns.
dr["TotalMarks"] = (float.Parse(dr["socialmarks"].ToString()) + float.Parse(dr["MathsMarks"].ToString()) + float.Parse(dr["ScienceMarks"].ToString())).ToString();

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OriginalGriff · Accepted Answer · 2015-12-27T22:42:00

Don't do that.
Please, stop relying on strings. When you do this:

C#

dr["TotalMarks"] = dr["socialmarks"].ToString() + dr["MathsMarks"].ToString() + dr["ScienceMarks"].ToString();

It performs string concatenation - so if the social marks are 17, the maths maths are 42 and the Science marks are 36, then the total marks will become "174236" - and dividing that by 3 is not going to produce a "reasonable" average! The situation becomes even worse if the marks aren't integers, because you end up trying to divide "17.042.036.0" by three and that makes no sense to anyone!

Instead, store your values in their native format: integers in integer fields, doubles in double columns, dates in DateTime columns, and so forth. That way, the storage all sorts itself out.

C#

int socialMarks = marks1.Next(50, 100);
int mathsMarks = marks2.Next(50, 100);
int scienceMarks = marks3.Next(50, 100);
int totalMarks = socialMarks + mathsMarks + scienceMarks;
dr["SocialMarks"] = socialMarks;
dr["MathsMarks"] = mathsMarks;
dr["ScienceMarks"] = scienceMarks;
dr["TotalMarks"] = totalMarks;
dr["AverageMarks"] = (double) totalmarks / 3.0;