Find the sum of the digits until only 1 digit remains

#include "stdafx.h"
#include <iostream>
using namespace std;

int main()
{
	int n, sum=0, total=0;
	cout << "Enter an integer." << endl;
	cin >> n;
	cout << "You have entered: " << n << endl;
	
	while (n > 0) {
	 sum += n % 10;
	 n /= 10;
	}

	cout << "The digitsum is: " << sum << endl;
	
	if (sum < 10)
	 cout << "The total digitsum is: "<< sum << endl;
	else 
	 do {
	  total += sum % 10;
	  sum /= 10;
	  cout << "The total digitsum is: " << total << endl;
	 } while (total < 10);
	
	system("pause");
	return 0;
}