opening the new window and bringing it on the front in asp.net

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opening the new window(browser) and bringing it on the front by button click whenever i clicked it will be open in front

C#

String open = "window.open(\"AJVErrorlog.aspx?ProjectCode=" + "1200" + "&ScheduleCode=" + EncrytedString(Session["ScheduleId"] as string) + "\",'mywindow', 'height=750,width=1200, menubar=0, resizable=yes')";
       ScriptManager.RegisterStartupScript(this.ctbUpdatePanel, this.ctbUpdatePanel.GetType(), "open", open, true);

Posted 22-Jul-15 1:51am

Sathish km

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Praveen Kumar Upadhyay 22-Jul-15 8:07am

What's wrong in your code?

Sathish km 22-Jul-15 8:14am

when i open this window by button click, it is showing front for first time only. after i click the button it still remains opened in background.
i want to show it in front whenever i clicked button.

Praveen Kumar Upadhyay 23-Jul-15 2:42am

It means window is already open and you are again clicking on button and want it to be active one?

Praveen Kumar Upadhyay 23-Jul-15 2:50am

Here I am posting my answer. This can help you.

Sathish km 23-Jul-15 5:07am

It means window is already open and you are again clicking on button and want it to be active one?

yes. it should open refreshed window

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Praveen Kumar Upadhyay · Accepted Answer · 2015-07-22T20:55:00

To open a window and to be active one always, you need to set the focus to that opened window.

Below is a sample example that can help you in your scenario.

XML

<html>
<head>
<script>
var newWindow = null;

function openWindow()
{
    if(newWindow==null)
    newWindow = window.open("http://www.google.in", '_blank','height=750,width=1200, menubar=0, resizable=yes');

    newWindow.focus();
}
</script>
</head>
<body>
<input type="button" value="Click" onClick="openWindow()"/>
</body>
</html>

You need to assign the window.open() to a global variable, if you do not want to open the new window always when you click on the button. At the end just set focus to that window object.
In the above example, whenever you click on button it will bring the opened(if not open) object in front.

In your example, rather passing the complete window object set, pass only the parameters to a javascript method and open window.open there in javascript method.

May be this hint can help you.