Pass a value to the next page in php

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anybody can help me please...

i had create this code to pass the value but it still return 0 to the next page...did i miss some code or i wrote the code wrong....

in the first page i had pass value one to next page..

<a href="kenal2.php?count=1"></a>

in the second page i had retrieve the value one and i had add the value with 1...

in the top page of the second page..

        if (isset($_GET['count']))<br />
            $count = $_GET['count'];<br />
        else<br />
            $count = 0;<br />
?>

at the bottom of the second page...i had done some calculation with the value

<?php echo $count;<br mode="hold" /?>      $sum = $count + 1; 
     ?>

so i want to pass the $sum value to the third page...

<a href="kenal3.php?count = $sum"></a>

in the top of third page...

        if (isset($_GET['sum';]))
            $sum = $_GET['sum'];
        else
            $sum = 0;
?>

when i try to show the value...it should come out with 2 but value 0 that had been show..seem that it could not retrieve the value from second page...
why this happen...

Posted 28-Mar-11 9:44am

LearningPerson

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Raj Bose · Answer 1 · 2011-03-28T10:09:00

Solution 1

May be this is the wrong syntex

<a href="kenal3.php?count = $sum"></a>

You can try

<a href="kenal3.php?count = <? echo $sum; ?>></a></pre></xml>"></a>

Posted 28-Mar-11 10:09am

Raj Bose

Comments

LearningPerson 29-Mar-11 0:44am

i had try the code...but it still can't get the value that i sum in second page and show in third page....

LearningPerson 29-Mar-11 0:54am

it seem that it has pass the value to third page but the third can't show the value...

leotraderpro · Answer 2 · 2011-09-08T10:58:00

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