open picture from right click menu context in c#

Question

1.00/5 (1 vote)

See more:

Hi i made my program in windows right click but when i right click the picture and open it in my program it doesn't show in the picturebox, how can i make it to open in picturebox?
these are my question pictures
Right Click context on image in windows[^]
this is my prgram image[^]

Posted 15-Nov-14 6:03am

Avenger1

Updated 15-Nov-14 11:18am

v2

Add a Solution

Comments

Nelek 15-Nov-14 16:08pm

Don't think we can read minds or do astral projections to see your monitor. If you need help, the least you could do is to add some relevant code to your question or to explain your problem in such a way, that the users of CP can understand it. Otherwise, nobody will be able to help you.

Please use the "improve question" and add relevant information or a piece of code envolved. There are thousands of ways to screw things up, how are we supposed to know which one did you choose?

Please read:
What have you tried?[^]
How to ask a question?[^]
best way to post code snippets[^]

Those links will help you to improve the quality of your question and hence the probability to get the answer you are looking for

Avenger1 15-Nov-14 17:19pm

i improved my question please someone answer what should i do
Best Regards

[no name] 15-Nov-14 18:23pm

What code have you tried?

Sergey Alexandrovich Kryukov 15-Nov-14 19:53pm

There is no such concept "open a PictureBox" (was it closed? :-). You need to explain exactly what do you want to achieve. Read the "What have you tried" article referenced by Nelek.
—SA

Avenger1 15-Nov-14 23:31pm

this is the code i tried but it just work for "open with"
string[] args = System.Environment.GetCommandLineArgs();
for (int i = 0; i <= args.Length - 1; i++)
{
if (args[i].EndsWith(".exe") == false)
{
open.FileName = args[i];
pictureBox1.Image = Image.FromFile(open.FileName);
//pictureBox1.Image = Image.FromFile(args[i]);
}
}
and this one but this one don't do anything
Registry.ClassesRoot.OpenSubKey(@"HKEY_CLASSES_ROOT\jpegfile\shell\NewMenuOption\m", true);

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2014-11-16T00:04:00

Solution 1

Probably, it's actually to do with how you added the application to the Associated Files list in the registry: You need to specify the file as a parameter there in order for windows to pass it through.
See here: http://stackoverflow.com/questions/10892433/open-file-with-association[^]

Posted 16-Nov-14 0:04am

OriginalGriff

Comments

Avenger1 17-Nov-14 8:31am

i don't understand how to use that code
can you help me to write that code?
Best Regards

OriginalGriff 17-Nov-14 8:40am

It's already written!

Avenger1 17-Nov-14 12:41pm

i said i didn't understand, my English isn't good
please help me to write that code