How Can I Show Up A Search Result In A Textbox

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Hi everybody,

I’ve created a table Code and would like to search and retrieve an answer introducing device Imei in textbox imei und when I click on the search want display the result(code_mck)in textbox code i want display the result

CSS

Code
 Imei               code_mck
 356885021519453    830782136

Initially I’ve typical three layer architecture and the search method is in

the Data Layer

public class unlockDAL
{              
    string strConn = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\Users\setup\Desktop\unlock\sim_unlock.accdb";        
    OleDbCommand cmd = new OleDbCommand();
 
    public DataSet recherche(string code)
    {
        DataSet ds = null;
        try
        {
          OleDbConnection cnn = new OleDbConnection(strConn);
          cnn.Open();
          string Oledb = "select*from Code where Imei=" + code + "";
        
          OleDbDataAdapter adapter = new OleDbDataAdapter(Oledb, cnn);
          ds = new DataSet();
          adapter.Fill(ds, "Code");
          cnn.Close();
        }
        catch
        {
          throw;
        }
        return ds;    
    }

Posted 3-Jul-14 7:19am

lira meh

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[no name] 3-Jul-14 13:39pm

And you still have not told us what the actual problem is.

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OriginalGriff · Answer 1 · 2014-07-03T08:38:00

Well, that just returns a DataSet so it should be pretty trivial:

C#

DataSet found = recherche("356885021519453");
if (found.Tables.Count > 0)
    {
    DataTable dt = found.Tables[0];
    if (dt.Rows.Count > 0)
        {
        myTextBox.Text = (string)dt.Rows[0]["code_mck"];
        }
    }

But please, don't do it like that! Never concatenate strings to build a SQL command. It leaves you wide open to accidental or deliberate SQL Injection attack which can destroy your entire database. Use Parametrized queries instead.
And your try...catch block doesn't actually do anything...
Try this:

C#

public DataSet recherche(string code)
    {
    DataSet ds = null;
    using (OleDbConnection cnn = new OleDbConnection(strConn))
        {
        cnn.Open();
        string Oledb = "SELECT * FROM Code WHERE Imei=@IMEI";
        using (OleDbDataAdapter adapter = new OleDbDataAdapter(Oledb, cnn))
            {
            adapter.SelectCommand.Parameters.AddWithValue("@IMEI", code);
            ds = new DataSet();
            adapter.Fill(ds, "Code");
            }
        }
    return ds;
    }