error 403 in php code

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hey,

i am trying to display some text on click of button in php. i am using dreamweaver and xamp for windows 8. i have tried so many solution but unfortunately none helped me out. Please provide me an appropriate solution for that.
waiting for replies.

Thanks in advance.

Posted 23-Dec-13 22:06pm

ritika luthra

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Sergey Alexandrovich Kryukov 24-Dec-13 12:48pm

It means "forbidden". Can be anything. Not enough information. You need to debug the server-side code.
—SA

ritika luthra 25-Dec-13 5:33am

yes, its the forbidden error.i have done everything; evn i have updated my config files but no solution.

CHill60 25-Dec-13 10:15am

Unfortunately we cannot see your code so we cannot help

Er. Tushar Srivastava 27-Dec-13 16:28pm

You need to at least provide with a small config data of your server. Is the folder in which your script is residing is accessible? Please consider revising the question. :)

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kishore@cse · Answer 1 · 2014-04-20T18:28:00

Just use jquery

First include jquesy js file in your page they try this code

HTML

<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
function show_data()
{
  $.post("another.php",function(data){
    $("#data_div").html(data);
  });
}
</script>
<input type="button" values="Click" onclick="show_data()">
<div id="data_div">
</div>
</input>

The contents that are executed in another.php will be seen in the division having id data_div