I want to display Name and code in drop down

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I want to display Name and code in drop down My query is Select Temp_Name,Temp_Code from Temp_Shipper
Drop Down list is ddlshipper in which Shipper name will come from query and other one is textbox8 in which code will come.

Posted 4-Dec-13 18:43pm

glmjoy

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Comments

TrushnaK 5-Dec-13 0:49am

post,what you have done so far?

Karthik_Mahalingam 5-Dec-13 1:12am

Please take your time and point out the need clearly..
add some code piece

glmjoy 5-Dec-13 7:38am

Thanks to all

3 solutions

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Tadit Dash (ତଡିତ୍ କୁମାର ଦାଶ) · Answer 1 · 2013-12-04T21:00:00

C#

DataTable shippers = new DataTable();

using (SqlConnection con = new SqlConnection(connectionString))
{

    try
    {
        SqlDataAdapter adapter = new SqlDataAdapter("Select Temp_Name,Temp_Code from Temp_Shipper", con);
        adapter.Fill(shippers);

        ddlshipper.DataSource = shippers;
        ddlshipper.DataTextField = "Temp_Name";
        ddlshipper.DataValueField = "Temp_Code";
        ddlshipper.DataBind();
    }
    catch (Exception ex)
    {
        // Handle the Exception
    }

}

// Add the initial item
ddlSubject.Items.Insert(0, new ListItem("<Select Shipper>", "0"));

Now handle SelectedIndexChanged Event of DropDown and assign the value to TextBox.

C#

void Shipper_Index_Changed(Object sender, EventArgs e) 
{
    textbox8.Text = ddlshipper.SelectedItem.Value;
}

Markup of DropDownList is like...

HTML

<asp:DropDownList id="ddlshipper" runat="server" AutoPostBack="True" OnSelectedIndexChanged="Shipper_Index_Changed">
</asp:DropDownList>

Reshma Babu · Answer 2 · 2013-12-04T19:40:00

ASP

<asp:DropDownList ID="DropDownList1" runat="server" AutoPostBack="True"
            onselectedindexchanged="DropDownList1_SelectedIndexChanged">
        </asp:DropDownList>

In page load, after setting data source,

DropDownList1.SelectedItem.Text=name;
DropDownList1.SelectedItem.Value= code;

In DropDownList1_SelectedIndexChanged method,
You can set the textbox value to DropDownList1.SelectedItem.Value

Aravindba · Answer 3 · 2013-12-04T22:13:00

Solution 3

hai
just use Solution 2 , in that concate the name and code like

C#

ddlshipper.DataSource = shippers;
        ddlshipper.DataTextField = "Temp_Name" + " " + "Temp_Code";
        ddlshipper.DataValueField = "Temp_Code";
        ddlshipper.DataBind();

Posted 4-Dec-13 22:13pm

Aravindba