How to select or not select a row depending on the value of another row in mysql

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+----------+------------+
| name     | code       |
+----------+------------+
| Fluffy   | 000        |
| Claws    | 217        |
| Buffy    | 598        |
| Fang     | 000        |
| Bowser   | 687        |
| Chirpy   | 587        |
| Whistler | 258        |
| Slim     | 298        |
| Fluffy   | 168        |
+----------+------------+

Here's my problem... in the above table the default value for column "code" is 000.In the column "name", Fluffy has 2 code one is the default 000 & the other one 168 When selecting, if fluffy has something other than the default code i've to select that & other rows leaving out the one row with default for Fluffy.Any way to do that with mysql IF or any other ? Hope my question is clear.

Posted 14-Nov-13 22:46pm

Akhil Das

Updated 14-Nov-13 22:47pm

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GuyThiebaut 15-Nov-13 5:05am

I don't understand what you are trying to do.
Can you give an example using data to illustrate what your expected result is - the example you give above only shows some of the data, I need to see more data and the result you expect to understand what you are wanting to do.
Thanks.

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OriginalGriff · Answer 1 · 2013-11-14T23:51:00

Solution 1

That's actually really nasty! :laugh:
But it can be done.
I doubt if this is the most efficient way, but...

SQL

SELECT name, code FROM MyTable m 
WHERE code<>0 
   OR (SELECT COUNT(code) FROM MyTable t 
       WHERE m.name = t.name)=1

Posted 14-Nov-13 23:51pm

OriginalGriff