C based question( Why k comes to zero).........................................................

Question

1.57/5 (3 votes)

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C

int main()
{

int i=-3,j=2,k=0,m;
m=++i&& ++j||++k;
printf("%d%d%d%d",i,j,k,m);
return 0;

}

My answer is

i=-2
j=3
k=1
m=1

Actual answer
i=-2
j=3
k=0
m=1

Question how this k comes to 0(zero)

Posted 17-Jul-13 20:15pm

patil.nitin8358

Updated 17-Jul-13 20:35pm

v4

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4 solutions

Solution 1

This is not C# and cannot compile as C#. You should not be so inaccurate if you want help.

—SA

Posted 17-Jul-13 20:22pm

Sergey Alexandrovich Kryukov

Comments

patil.nitin8358 18-Jul-13 2:41am

if u know it then only u can answer it. for ur information c & C# logic is same dont go on language just answer if u know

Sergey Alexandrovich Kryukov 18-Jul-13 3:02am

What you say makes no sense. "Same logic" is simply not true. You are asking the question where the difference is essential. "For your information"...
—SA

Sergey Alexandrovich Kryukov 18-Jul-13 3:12am

Look at the operator precedence, evaluation of || and see if ++k has to be evaluated or not. If not, it won't be incremented.
—SA

H.Brydon 18-Jul-13 3:26am

+5 for enduring the pain of the downvote. :-)

Sergey Alexandrovich Kryukov 18-Jul-13 10:34am

Thank you, Harvey. By the way, there is no a downvote at the moment...
—SA

H.Brydon 18-Jul-13 13:08pm

There was when I upvoted it. I suppose the downvoter changed their mind...

Well you deserved both +5. Don't complain about it. :-)

Sergey Alexandrovich Kryukov 18-Jul-13 14:35pm

Sure. I notice that it worth to respect people enough to give them your arguments. The common notion that arguments are useless and don't worth effort is plain wrong. Many people are reasonable and cannot listen to arguments. Even of many, or even of majority is not reasonable enough, it's worth explaining things for those who are.
Thank you again.
—SA

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Thanks7872 · Accepted Answer · 2013-07-17T20:23:00

Solution 2

Refer to this link

How function works[^]

Posted 17-Jul-13 20:23pm

Thanks7872

Comments

patil.nitin8358 18-Jul-13 2:48am

if u know it then only u can answer it. for ur information dont go on language just answer if u know the answer reply it

Thanks7872 18-Jul-13 2:54am

Have you gone through that link? Its an answer to your question. We are not here to do homework for you.

Sergey Alexandrovich Kryukov 18-Jul-13 3:04am

My 5.
—SA

Thanks7872 18-Jul-13 3:06am

It really hurts me when i find that such a wonderful place is being spammed through questions like this. Its very sad for me.

Sergey Alexandrovich Kryukov 18-Jul-13 3:17am

Well, this question is by far not the worse, if we compare it with others these days, but I'm also concerned with the quality of questions and many answers which goes down. After all, reputation of the resource suffers. After all, people who really deserve help and can use it may go away...
—SA

patil.nitin8358 18-Jul-13 3:02am

To Rohan Leuva,

I think u don't know the answer , this may happenned because of overconfidenc. If u know the answer then u can answer it. i think u have no answer.

every one try to pull out legs of other who want to improve.

Sergey Alexandrovich Kryukov 18-Jul-13 3:05am

Would you stop making baseless statements?
If you really wanted to improve, you would simply use the debugger, to see how calculation goes, and read the reference on those operators.
—SA

Sergey Alexandrovich Kryukov 18-Jul-13 3:22am

The worse thing is: you are trying to manipulate people. Hoping that someone will buy your "challenge" to avoid showing incompetence? Ridiculous. Most people are not that cheap.
—SA

patil.nitin8358 18-Jul-13 3:09am

k=0;
i have preincremented it. then it become 1
why k is o as answer.
I know how to debug the program very well.

Sergey Alexandrovich Kryukov 18-Jul-13 3:14am

I don't say you don't know how to debug, it's strange that you did not do it if you know... I gave you some hint, it should be enough.
—SA

patil.nitin8358 18-Jul-13 3:20am

The use of operators..
use of logical operator the first && operators is works due to preceding high priority so i and j increment with 1 and due to || operator it works only for j not for k .. you can swap j and k then you can get j is not increment but k will increment.

Sushil Mate 18-Jul-13 5:13am

my +5

Thanks7872 18-Jul-13 13:03pm

Thanks sushil.

Hemant Singh Rautela · Accepted Answer · 2013-07-17T21:14:00

Solution 3

Hi,
Your answer is in your question..:-)

The use of operators..
use of logical operator the first && operators is works due to preceding high priority so i and j increment with 1 and due to || operator it works only for j not for k .. you can swap j and k then you can get j is not increment but k will increment.

Due to || operator any one condition is true, It works...

m=++i&& ++j||++k;

:-)

Posted 17-Jul-13 21:14pm

Hemant Singh Rautela

Updated 17-Jul-13 21:34pm

v2

Comments

patil.nitin8358 18-Jul-13 3:19am

so i need to check priority of logical operator

Hemant Singh Rautela 18-Jul-13 3:33am

Its all not on base priority its base on || operator...

User 59241 · Accepted Answer · 2013-07-17T21:38:00

Solution 4

Google should always be your first port of call. It can save everyone much angst.

http://stackoverflow.com/questions/16271779/why-isnt-k-incremented-in-the-statement-m-i-j-k-when-i[^]

Posted 17-Jul-13 21:38pm

User 59241

Updated 17-Jul-13 23:14pm

v2