How to compare each word of a string and return values like 1 and 0?

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so i tried below code but every time the sum value showing zero only

C#

for (i = 0; Yname[i] != null; i++)
          {

              for (j = 0; Pname[j] != null; j++)
                  if (String.Equals(Yname[i], Pname[j], StringComparison.OrdinalIgnoreCase) == false)
                  {
                      Sum = Sum + 1;
                  }
          }

Posted 5-Apr-13 19:00pm

Vishal_Prince

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OriginalGriff · Accepted Answer · 2013-04-05T21:09:00

I don't I tried your code as written, and it gave me positive numbers:

C#

string[] Yname = { "hello", "there", "Paul" , null};
string[] Pname = { "goodbye", "there", "paul" , null};
int Sum = 0;
int i, j;
for (i = 0; Yname[i] != null; i++)
    {

    for (j = 0; Pname[j] != null; j++)
        if (String.Equals(Yname[i], Pname[j], StringComparison.OrdinalIgnoreCase) == false)
            {
            Sum = Sum + 1;
            }
    }

Run this, and Sum was 7
The only way you would get zero, is if the first element of either of your string arrays was null, or if all the strings were the same, of the first element of Pname was null.

What are you trying to achieve? Not "get the code working" but why are you writing this code? (And why are you writing it like that?)

"ok i'll try again.
me developing a love meter application.user enters his and his partner name into textboxes when user clicks the button he get results like "love","marriage" etc
in button click i want to compare each of the single characters."

Ah! Try this:

C#

string Yname = "hello";
string Pname = "goodbye";
int Sum = 0;
int i, j;
Yname = Yname.ToLower();
Pname = Pname.ToLower();
foreach (char y in Yname)
    {

    foreach (char p in Pname)
        {
        if (y != p)
            {
            Sum++;
            }
        }
    }

(The first two lines are just for me to test - you will want your textboxes)
This code does what your first code did, but using characters. So with the two string I show, it gives 32 - because it counts each of the characters in Pname for each of the characters in Yname.

If what you want is a count of the number of characters that are in both strings (and I suspect you do) then reverse the if condition from "!=" to "==" and you will get 3 - the 'e', plus the 'o' twice.

Pallavi Waikar · Accepted Answer · 2013-04-06T02:15:00

Solution 2

try this code

C#

string[] Yname = { "hello", "there", "Paul" , null};
string[] Pname = { "goodbye", "there", "paul" , null};
int Sum = 0;
int i, j;
foreach (string name in Yname)
{
      if (Pname.Contains(name))
      {
          Sum = Sum + 1; 
      }
}

updated solution as per ur comment

C#

string[] Yname = txtUrNa.Text.ToString().Split(',');
string[] Pname = txtPrNa.Text.ToString().Split(',');
int Sum = 0;
foreach (string name in Yname)
{
     if (Pname.Contains(name))
     {
        Sum = Sum + 1;
     }
}

Posted 6-Apr-13 2:15am

Pallavi Waikar

Updated 6-Apr-13 3:29am

v2

Comments

Vishal_Prince 6-Apr-13 8:35am

thanks.I used this code too, But still not getting what i want.
every time i am giving same name,but every time the results are different.

Pallavi Waikar 6-Apr-13 8:58am

give one example of value u adding in textbox

Vishal_Prince 6-Apr-13 9:01am

me not giving values,Names of peoples like "Radha","Ram",etc

Pallavi Waikar 6-Apr-13 9:49am

check updated solution

Vishal_Prince 7-Apr-13 9:39am

thanks for the help