Replace the last file name in path

Question

2.50/5 (2 votes)

See more:

C#

Path= @"G:\Trial\WorkDirectory\Kabhi Kabhi Aditi\abc.npr"; want to replace abc.npr with xyz.xml

Posted 30-Aug-12 23:25pm

Sachin Adsul

Add a Solution

Comments

BillW33 3-Sep-12 10:27am

If one of the solutions given answers your question you should mark it as the answer so that this question gets removed from the list of unanswered questions.

5 solutions

Solution 5

C#

string originalPath = @"G:\Trial\WorkDirectory\Kabhi Kabhi Aditi\abc.npr";
originalPath = originalPath.Replace(Path.GetFileName(originalPath), "xyz.xml");

Posted 31-Aug-12 5:58am

Kuthuparakkal

Comments

lewax00 31-Aug-12 12:09pm

This will cause problems if the path ever contains the filename somewhere else ("." is valid in directory names, so a path like "G:\Trial\WorkDirectory\abc.npr\Kabhi Kabhi Aditi\abc.npr" is possible).

Kuthuparakkal 3-Sep-12 8:25am

Agreed...

Solution 1

Hello,

Check below code it will used replace file name with new file name

C#

string ReplaceText = @"G:\Trial\WorkDirectory\Kabhi Kabhi Aditi\abc.npr";
            ReplaceText = ReplaceText.Replace(ReplaceText.Substring(ReplaceText.LastIndexOf(@"\") + 1, ReplaceText.Length - (ReplaceText.LastIndexOf(@"\") + 1)), "xyz.xml");

Thanks
Gaurav Dhol

Posted 30-Aug-12 23:44pm

Dhol Gaurav

Comments

lewax00 31-Aug-12 12:06pm

Technically correct (at least it appears to be, I haven't tested it), but it's very unclear and much more complicated than it needs to be.

Solution 2

Use this:

C#

string path = @"G:\Trial\WorkDirectory\Kabhi Kabhi Aditi\abc.npr"
string filename = Path.GetFileName(path);

Refer Path.GetFileName Method[^].

--Amit

Posted 30-Aug-12 23:59pm

_Amy

Comments

lukeer 31-Aug-12 6:41am

But the filename is exactly that part, that the OP is not interested in.

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

lukeer · Accepted Answer · 2012-08-31T00:38:00

Solution 3

Go for the methods in System.IO.Path[^]:

C#

string originalPath = @"G:\Trial\WorkDirectory\Kabhi Kabhi Aditi\abc.npr";
string newFileName = "xyz.xml";

string newPath = System.IO.Path.Combine(
    System.IO.Path.GetDirectoryName(originalPath),
    newFileName
);

Posted 31-Aug-12 0:38am

lukeer

Updated 31-Aug-12 0:40am

v2

Comments

lewax00 31-Aug-12 12:07pm

Exactly, no need to reinvent the wheel, +5

lukeer 3-Sep-12 1:38am

Thanks.

BillW33 31-Aug-12 16:19pm

Short & sweet, +5

lukeer 3-Sep-12 1:38am

Thank you.

Christian Amado · Accepted Answer · 2012-08-31T04:37:00

Solution 4

C#

string path= @"G:\Trial\WorkDirectory\Kabhi Kabhi Aditi\abc.npr";
int index = path.LastIndexOf("\");
path = path.SubString(0,index);
path +="\zyz.xml" ;

Just another solution :)

Regards.

Posted 31-Aug-12 4:37am

Christian Amado

Updated 31-Aug-12 4:40am

v2

Comments

Christian Amado 31-Aug-12 13:31pm

Why downvoted?