Continuation of the program (loop for) after the catch block.

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A try and catch block is in the loop for.
The assumption is when i = 2 source code is transferred to the catch. After the catch block should loop from i = 3 to continue

Posted 29-Aug-12 6:53am

me64

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[no name] 29-Aug-12 13:00pm

At first read, your narractive (nowhere is there a question) does not make any sense. When you read it carefully, not only does it not make sense but what it is that you think that you are trying to do is totally and completely wrong.

BillW33 29-Aug-12 13:02pm

Post your source code and exactly where you are having a problem then someone will be able to help you.

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Clifford Nelson · Accepted Answer · 2012-08-29T08:00:00

Solution 2

The following does continue to 3 and 4 after an exception when i = 2:

C#

for (int i = 1; i < 4; i++)
{
    try
    {
        int s = 1 /(i - 2);
    }
    catch
    {
    }
}

Posted 29-Aug-12 8:00am

Clifford Nelson