Counting List Box Duplicate Items

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Hello all.

I have two list boxes. One of them is filled with file names and their directories.

I want to count all duplicate file names in the first list box and put the file name and the number of duplication in the second list box.

like: 0.TXT (6)

the program:http://img178.imageshack.us/img178/2160/82415716.png[^]

I use VC++, so please give me C++ code for I'm still a beginner. :((

Thanks in advance. :-O

Posted 6-Nov-10 8:38am

aim999

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Tamer Hatoum · Answer 1 · 2010-11-06T11:51:00

Solution 1

check that link even it is in vb.net but you can understand the algorithem of it :
link[^]

the trick is to create 2 nested loops :
while(i<listbox.count){>
for(k<listbos.count){>
// then check if(listbox[i]==listbox[k]){
then add this item to the new list ...
}}
regards...

Posted 6-Nov-10 11:51am

Tamer Hatoum

Updated 6-Nov-10 11:55am

v2

aim999 · Answer 2 · 2010-11-06T21:20:00

thanks a lot for the answer but I really couldn't understand many of it's expressions.

I googled it but all I found was VB code.

and about the idea you provided above, I tried it but it gives me an out of range exception.

here is what I did so far:

int L = listBox1->Items->Count::get();
int i = 0;
while(i<l)>
{
  i++;
  for(int k=0; k<l;>  
  {
    if(listBox1->Items[i]==listBox1->Items[k])
    {  
      listBox2->Items->Add(listBox1->Items[i]);
    }
  }
}

Sorry if I were wrong!

Tamer Hatoum · Answer 3 · 2010-11-07T01:16:00

Solution 3

yes sure it will give out of range I just gave an idea without giving the fulllogic ...
the trick is to start in the second loop where we have reached the last time ...

here is the logic :

for ( i=0;i<count;i++){>

for( j=i+1;j<count-i;j++){>

then do what ever you want }
}

regards...

Posted 7-Nov-10 1:16am

Tamer Hatoum

Comments

DaveAuld 7-Nov-10 7:21am

Do not use the Add Answer to have a discussion, use the Add Comment feature below the question or answer that you are discussing.....

aim999 7-Nov-10 8:19am

Well, it didn't work either. Am I missing something?
for(int i=0; i<l; i++)
for(int="" j="i+1;" j<(l-i);="" j++)
if(listbox1-="">Items[i]==listBox1->Items[j]) listBox2->Items->Add(listBox1->Items[j]);

Tamer Hatoum 7-Nov-10 8:34am

what is the error ??? can you post all of your code???

aim999 7-Nov-10 10:23am

Yes, sure but the comment block is not enough and when I post it as an answer it gets altered

aim999 · Answer 4 · 2010-11-07T04:33:00

C++

private: System::Void button1_Click(System::Object^  sender, System::EventArgs^  e) {
                 for(int x=0; x<=10; x++)
                 {
                     listBox1->Items->Add("D:\\QuakeII\\"+x+".TXT");
                 }
                 for(int y=0; y<=5; y++)
                 {
                     listBox1->Items->Add("E:\\Programs"+y+".TXT");
                 }
                 for(int z=0; z<=3; z++)
                 {
                     listBox1->Items->Add("F:\\Videos\\"+z+".TXT");
                 }
             }
    private: System::Void button2_Click(System::Object^  sender, System::EventArgs^  e) {
                 int L = listBox1->Items->Count::get();
                 for(int i=0; i<l;>                 {
                     for(int j=i+1; j<=(L-i); j++)
                     {
                         if(listBox1->Items[i]==listBox1->Items[j])
                         {
                             listBox2->Items->Add(listBox1->Items[j]);
                         }
                     }
                 }

It doesn't give an error and doesn't do anything too.

Counting List Box Duplicate Items

4 solutions

Solution 1

Solution 2

Solution 3

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