How to Add Record from Button Click event Record into data table

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I want to Add record into Data Table in multiple time One Button Click Event Without Declare DataTable as Static.

e.g. I want add 10 record into Data Table when User press 10 Time Button

I am using this code but not working every Click event Data Table Clear

C#

DataTable dt_dr = new DataTable("Test");

dt_dr.Columns.Add(LedgerId, typeof(int));
dt_dr.Columns.Add(LedgerName, typeof(string));


DataRow dt_row;
dt_row = dt_dr.NewRow();
dt_row[LedgerId] = TextBox1.Text;
dt_row[LedgerName] = TextBox2.Text;
dt_dr.Rows.Add(dt_row);

Posted 20-Nov-11 22:40pm

Member 8413260

Updated 21-Nov-11 0:20am

Anuja Pawar Indore

v6

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Comments

_Tushar Patil 21-Nov-11 4:46am

web application Or Windows App..?

Member 8413260 21-Nov-11 6:04am

web application

Sunasara Imdadhusen 21-Nov-11 5:03am

Is this our homework?

Member 8413260 21-Nov-11 6:06am

Its Office Work

2 solutions

Solution 1

On button click u make one manual datatable with your headers as columns.
then add rows with data dynamically.

Posted 21-Nov-11 0:02am

Manisha Tambade

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PBangale · Accepted Answer · 2011-11-21T01:04:00

Hello Anuja,
Declare an object of DataTable at class level

Use bellow code in button click event

C#

protected void Button1_Click(object sender, EventArgs e)
 {
     try
     {
         //Check if previous session is exist
         if (Session["MyTable"] == null)
         {
             dtMyTable = new DataTable("MyTable");
             dtMyTable.Columns.Add("Id", typeof(int));
             dtMyTable.Columns.Add("LName", typeof(string));

         }
         else
         {
             //If yes then get it from current session
             dtMyTable = (DataTable)Session["MyTable"];
         }

         //Add new row every time
         DataRow dt_row;
         dt_row = dtMyTable.NewRow();
         dt_row["Id"] = TextBox1.Text;
         dt_row["LName"] = TextBox2.Text;
         dtMyTable.Rows.Add(dt_row);

         //Update session table
         Session["MyTable"] = dtMyTable;
     }
     catch (Exception ex)
     {

         Response.Write(ex.Message);
     }
 }