C# WPF image not changing? ..............

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this is my code

int n=1;
    private void image1_MouseLeftButtonDown(object sender, MouseButtonEventArgs e)
    {
        if (n == 1)
        {
            myStoryboard.Begin(this);
            myStoryboarda.Begin(this);
            BitmapImage img = new BitmapImage();
            img.BeginInit();
            img.UriSource = new Uri("pack://application:,,/Resources/MB2.png");
            img.EndInit();
            image1.Source = img;
            n = 2;
        }
        else
        {
            myStoryboard2.Begin(this);
            myStoryboardb.Begin(this);
            BitmapImage img = new BitmapImage();
            img.BeginInit();
            img.UriSource = new Uri("pack://application:,,/Resources/MB2.png");
            img.EndInit();
            n = 1;
        }
    }

and i get an error on this line

img.EndInit();

and the error says

Cannot locate resource 'resources/mb2.png'.

and my resource is called " MB2 " and it is a png in my resources. and for some reason it just doesn't work and i don't know why, can some one please help me?

Posted 30-Jul-11 2:44am

C.CoderCreator

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2 solutions

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nit_singh · Answer 1 · 2011-07-30T03:25:00

Solution 2

create resource in the App.xaml

XML

<ImageSource x:Key="test1">banner_img_1.jpg</ImageSource>
<ImageSource x:Key="test2">banner_img_2.jpg</ImageSource>

Now change the source like that

C#

private void image1_MouseLeftButtonDown(object sender, MouseButtonEventArgs e)
       {
           image1.Source = this.FindResource("test2") as ImageSource;
       }

Posted 30-Jul-11 3:25am

nit_singh

Comments

[no name] 30-Jul-11 21:08pm

i get an error saying, resource not found

nit_singh 2-Aug-11 10:42am

Where did you created the resources in the App.xaml file?

Abhinav S · Answer 2 · 2011-07-30T02:53:00

Solution 1

This could be an issue with the url path.
Just try new URI(/Resources/MB2.png).

Posted 30-Jul-11 2:53am

Abhinav S

Comments

[no name] 30-Jul-11 8:56am

i get this error: Invalid URI: The format of the URI could not be determined.