Problem with openfiledialog in library C#

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I created a clr empty project that uses a ui, then is called a c# library, but I have problem with OpenFileDialog in c# library..sotware get into loop..Do you have an idea? tHIS is code of my main in c++:

<pre>#using "consume_cs_indexers.dll" //c# library

using namespace System;

#include "MyForm.h"

using namespace Project702;

int main()
{
	IndexerClass ^ ic = gcnew IndexerClass;
	//ic->default[0] = 21;
	//for (int i = 0; i <= 10; i++)
	//	Console::WriteLine("Element #{0} = {1}", i, ic->default[i]);

	int result = ic->Add(3, 6);


	System::String^ s = result.ToString();

	MyForm ^ fm = gcnew MyForm;

	//fm->Pr


	fm->MyString2 = s;
     fm->ShowDialog();

	ic->PrintLabelAction();

	//fm->ShowDialog();
}

code in my library c#:

public void PrintLabelAction()
   {
       OpenFileDialog openFileDialog = new OpenFileDialog();
       openFileDialog.Filter = "DYMO files |*.label;*.dymo|All files|*.*";

       var FileName = "";


       //var LabelObjects = "";
       if (openFileDialog.ShowDialog() == true) // in this raw code get into a loop
       {

What I have tried:

I tried to do call stack but is empty..

Posted 10-Mar-23 4:41am

Member 14594285

Updated 10-Mar-23 4:59am

v2

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Comments

Richard Deeming 10-Mar-23 10:43am

So you want us to help you fix a problem you can't describe in code we can't see running on a system we can't access?

That's not going to work. Click the green "Improve question" link and update your question to include a clear and complete description of the problem, the relevant parts of your code, and the full details of what you have tried and where you are stuck.

Member 14594285 10-Mar-23 10:59am

done

Jo_vb.net 10-Mar-23 11:32am

Your If statement is fulfilled when then dialog button ok is pressed - not earlier.

Perhaps this example helps:

dialog.ShowDialog();
if (string.IsNullOrEmpty(dialog.FileName))
return default;
string FileName = Path.GetFileName(dialog.FileName);

Member 14594285 10-Mar-23 11:41am

it's the same thing..in dialog.ShowDialog() software get into a loop

Jo_vb.net 10-Mar-23 12:02pm

When you have the file name you will do some more instructions.
OK button will be pressed at some time...
Then:
return default;

string FileName = Path.GetFileName(dialog.FileName);

// more instructions

// OK button is pressed

return default;

Member 14594285 10-Mar-23 12:03pm

but I can't do this because in dialog.ShowDialog software blocks and gets into a loop

Jo_vb.net 10-Mar-23 12:11pm

Please show us your complete method PrintLabelAction()

Jo_vb.net 10-Mar-23 12:35pm

Can you compile your C# library without any errors?

When the FileDialog is opened, the program waits until you select a file and press dialog button OK or until the button CANCEL is pressed.
Only then the program goes on.

Shao Voon Wong 10-Mar-23 23:52pm

You cannot call UI dialog in a console application because there is no message queue to pump the message. You cannot call .NET UI like WinForm in C++/CLI. Microsoft says C++/CLI is for non-UI code that needs to access native C++ code.

Member 14594285 13-Mar-23 3:52am

but now my application is with ui because I used a windows form ui and now I have a dialog..so is there a way to use OpenFileDialog

Member 14594285 13-Mar-23 5:43am

I solved with a thread

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