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Hello everyone, please I want to understand why the code below is returning a "false" from the command prompt. I passed the argument from the command line. I know that the Boolean.valueOf("a string") would convert a String into a Boolean type and saving into a primitive type boolean "b" is possible by Auto-Unboxing in java. Please is it comparing a String to a boolean primitive tpye ? Thanks for any help.

boolean b = new Boolean(Boolean.valueOf(args[0]));
		System.out.println(b);

This is how the argument is passed from command line, the class name is Test.
javac Test.java
java Test 1

What I have tried:

boolean b = new Boolean(Boolean.valueOf(args[0]));
		System.out.println(b);
Posted
Updated 8-Mar-23 19:57pm

1 solution

Look at the documentation: Java.lang.Boolean.valueOf() Method[^]
Quote:
The Boolean returned represents a true value if the string argument is not null and is equal, ignoring case, to the string "true".
Since "1" is not teh same as "true", "TRUE", "True" or any other combination you will always get false as a result.
Try this instead:
javac Test.java
java Test true
 
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Comments
CPallini 9-Mar-23 2:21am    
5.
UT7 9-Mar-23 2:25am    
@OriginalGriff Got it! Thanks a lot.
OriginalGriff 9-Mar-23 3:46am    
You're welcome!

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