How do I join a list inside a list every 2 list

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For example I have a list of:

[[1,1,1], [1,1,0], [1,0,1], [1,0,1], [1,1,1], [1,1,0], [1,0,1], [1,0,1], [1,0,1], [1,1,0]]

I want it to be:

[[1,1,1,1,1,0], [1,0,1,1,0,1], [1,1,1,1,1,0], [1,0,1,1,0,1], [1,0,1,1,1,0]]

If you don't get it here is another example:

[a, b, c, d, e, f, g, h, i, j]

[ab, cd, ef, gh, ij]

What I have tried:

list = [[1, 1, 1], [1, 1, 0], [1, 0, 1], [1, 0, 1], [1, 1, 1], [1, 1, 0], [1, 0, 1], [1, 0, 1], [1, 0, 1], [1, 1, 0]]
newlist = []
for i in range(int(len(list)/2)):
    newlist = (''.join(list for n in range(2)))

print(newlist)

Posted 8-Nov-22 1:30am

Jethy11

Updated 8-Nov-22 1:51am

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CPallini · Accepted Answer · 2022-11-08T01:51:00

Solution 1

Try

Python

l0 = [[1, 1, 1], [1, 1, 0], [1, 0, 1], [1, 0, 1], [1, 1, 1], [1, 1, 0], [1, 0, 1], [1, 0, 1], [1, 0, 1], [1, 1, 0]]
l1 = [ l0[n]+l0[n+1] for n in range(len(l0)) if n%2 == 0 ]
print(l1)

Posted 8-Nov-22 1:51am

CPallini

Comments

Richard MacCutchan 8-Nov-22 11:19am

+5, nice.

CPallini 8-Nov-22 15:57pm

Thank you.