Why the copy constructor not invoked for the a3 object in below code?

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C++

constructor

#include <iostream>

using namespace std;
class A 
{
  int x;
  public:
  A(){
      cout<<"default constructor called\n";
  }
  A(int a)
  {
      x=a;
  }
  A(const A&p)
  {
      cout<<"Copy constructor called\n";
      x=p.x;
  }
  
  A operator+(A &p)
  {  
      cout<<"+ called\n";
      A temp;
      temp.x=x+p.x;
      return temp;
  }
};
int main()
{
    // cout<<"Hello World";
A a1(3),a2(4);
A a3=a1+a2;
    return 0;
}

What I have tried:

I tried googling but nothing found. See in above code I have written the statement inside each constructor to determine which is called.

In the line-
A a3=a1+a2;
here a1 will call + operator and a2 will be passed as an argument to the + operator function so "+ called" gets printed on console . Now inside + operator temp object created so for that default constructor gets called and "default constructor called" gets printed on console. So when + operator returns temp so then copy constructor must be called for a3 because now the line becomes - A a3 = temp;
but the values are copied inside a3 because I have printed on console but how no assignment operator , copy constructor called . If copy constructor gets called then it must be printed "Copy constructor called" on console.