I need to display a picture of a triangle

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The user decides on the maximum width of the isosceles triangle. Use a validation loop to ensure their input is between 2 and 7 (inclusive). Use nested loops to make the triangle, which is composed of boxes, appear on the screen. For example, for this one, the width would be 2.

 -
| |
 -
 -   -
| | | |
 -   -

What I have tried:

for (int n = 1; n<= tri_width; n++){
				for (int i = 1; i <= tri_width; i++){
					cout << "-";
					for (int j = 1; j<= tri_width; j++){
						cout << "| |";
						for (int k = 1; k <= tri_width; k++){
							cout << "_";
						}
					}
				}
				cout << endl;
			}
			cout << endl;

Posted 6-Oct-22 7:11am

gkau

Updated 8-Oct-22 9:26am

v4

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jeron1 6-Oct-22 13:26pm

What is your question?

merano99 6-Oct-22 13:51pm

Based on Greg's response, I formatted the text to get a better view of the desired output.
The code shown does not match the desired result and an question ist still missing.

3 solutions

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Greg Utas · Answer 1 · 2022-10-06T07:54:00

What you have "tried" just prints a row of hyphens. You've been told that you need to use nested loops, so think about how you would do this manually. A number 2<=n<=7 is entered. In the first row, you need to draw a single box, but three lines of output are needed to create a box:

ASCII

 -
| |
 -

The nth row will contain n boxes, and each row requires 3 lines of output. The first and last of those 3 lines will contain hyphens. The middle row will contain vertical bars with gaps.

Based on this, take a shot at writing the code.

EDIT#1: If this is going to be a true isosceles triangle, the first row must be indented so its box is centered. Only the last row won't be indented.

EDIT#2: To clarify, the output for three boxes should probably look like this:

ASCII

     -
    | |
     -
   -   -
  | | | |
   -   - 
 -   -   -
| | | | | |
 -   -   -

or even this in standard ASCII art :)

ASCII

    +-+
    | |
    +-+
  +-+ +-+
  | | | |
  +-+ +-+ 
+-+ +-+ +-+
| | | | | |
+-+ +-+ +-+

merano99 · Answer 2 · 2022-10-06T13:45:00

The current source code now looks like this:

C++

for (int i = 0; i <= tri_width; i++) {
	cout << "-";
	for (int j = 1; j <= tri_width; j++) {
		cout << "| |";
		for (int k = 1; k <= tri_width; k++) {
			cout << "_";
		}
	}
}
cout << endl;

and produces the following output with a width of 2 :

- | | __ | | __ - | | __ | | __ - | | __ | | __

but it should be:

 -
| |
 -
 -   -
| | | |
 -   -

Obviously, some things are still not right. Line breaks and spaces are missing and there are way too many characters. With width 2 you can see that only 12 visible characters are expected.

Since three lines are required to create a box and several boxes are next to each other, it would probably be advisable to first assemble the three lines into three strings before outputting them and only output them when the line is complete.

merano99 · Answer 3 · 2022-10-08T09:26:00

Here is a suggestion to wrap the boxes in a C++ variable. The main program becomes trivially simple, since all annoying things happen encapsulated in the class.

C++

strbox boxout, newbox;

// Draw everythin on screen
for (int i = 0; i < tri_width; i++) {
   cout << boxout;
   boxout += newbox;
}

To implement the variable strbox you need a class that could look like this:

C++

class strbox {
public:
	strbox();  // default constructor
	strbox& operator+=(strbox& nb);
	friend ostream& operator<<(ostream& os, strbox& dt);
	std::string get_l(unsigned n);
	void clear();
private:
	std::string _l[3];
};

Now only the methods themselves have to be programmed. I present here only the frameworks.

C++

strbox::strbox() {  clear(); }
void strbox::clear() { _l[0] = " - "; _l[1] = "| |"; _l[2] = " - "; }
std::string strbox::get_l(unsigned n) { /* TODO	*/}
// declare addition operator that adds two Box objects and returns final Box object
strbox& strbox::operator+=(strbox& nb) { /* TODO */  return *this; }
ostream& operator<<(ostream& os, strbox& sbo) { /* TODO */ return os; }

I need to display a picture of a triangle

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