Can anyone solve this problem in C language?

Question

1.00/5 (1 vote)

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How to find frequency of characters in each line of a passage in C?
I've managed to count the frequency of all characters in a given passage but can't find the frequency of characters line by line.

What I have tried:

#include<stdio.h>
#include<string.h>
int main()
{
int i;
char str[1000];
int arr[26]={0};
gets(str);
for(i=0;i<strlen(str);i++)
{
 if(str[i]>='a' && str[i]<='z')
 {
 int temp=str[i]-'a';
 arr[temp]++;

 }
else if(str[i]>='A' && str[i]<='Z')
{

int temp=str[i]-'A';
arr[temp]++;

}
else
continue;

}
for(i=0;i<26;i++)
{

printf("%c=%d\n",i+'a',arr[i]);


}





}

Posted 5-Sep-22 9:08am

Rulerz Life

Updated 6-Sep-22 21:08pm

v2

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Patrice T · Answer 1 · 2022-09-06T20:33:00

Quote:
How to find frequency of characters in each line of a passage in C?

All what you do to get the result for a single input, you will have to do for each input line.
You need to find how to input many times, with how to know that input is finished. With every input line , apply same procedure to get frequency on the line.
Nota: you may want to skip letters seen zero times, and you may want to have more than a single letter per result line.

Advice: learn to search C++ reference gets - C++ Reference[^]

Advice: Learn to indent properly your code, it show its structure and it helps reading and understanding. It also helps spotting structures mistakes.

C++

#include <stdio.h>
#include <string.h>

int main()
{
	int i;
	char str[1000];
	int arr[26] = { 0 };
	gets(str);
	for (i = 0; i < strlen(str); i++)
	{
		if (str[i] >= 'a' && str[i] <= 'z')
		{
			int temp = str[i] - 'a';
			arr[temp]++;
		}
		else if (str[i] >= 'A' && str[i] <= 'Z')
		{

			int temp = str[i] - 'A';
			arr[temp]++;
		}
		else
			continue;
	}
	for (i = 0; i < 26; i++)
	{

		printf("%c=%d\n", i + 'a', arr[i]);
	}
}

Indentation style - Wikipedia[^]
Best C++ Formatter and Beautifier[^]
Online C/C++ Formatter, Indenter and Beautifier – Techie Delight[^]

Professional programmer's editors have this feature and others ones such as parenthesis matching and syntax highlighting.
Notepad++ Home[^]
ultraedit[^]
Enabling Open Innovation & Collaboration | The Eclipse Foundation[^]

CPallini · Answer 2 · 2022-09-06T21:08:00

Solution 5

The isalpha, toupper, functions are handy, for such a task:

C

#include <stdio.h>
#include <ctype.h>

enum
{
  LETTERS = 'Z'-'A'+1,
};

int main()
{
  int c;
  int freq[LETTERS] = {0};
  while ((c = getchar()) != EOF)
  {
    if ( c == '\n')
    {
      for (int n=0; n<LETTERS; ++n)
      {
        printf("%c %4d\n", ('A'+n), freq[n]);
        freq[n] = 0;
      }
    }
    else
    {
      if ( isalpha(c) )
      {
        ++freq[toupper(c)-'A'];
      }
    }
  }
  return 0;
}

Posted 6-Sep-22 21:08pm

CPallini

Comments

merano99 7-Sep-22 3:54am

My 5

Patrice T 7-Sep-22 7:44am

What if input is lowercase ?
+5

CPallini 7-Sep-22 8:48am

++freq[toupper(c)-'A'];
takes care of it.
BTW Thank you!

Patrice T 7-Sep-22 8:55am

missed it :)

Richard MacCutchan · Answer 3 · 2022-09-05T09:24:00

The first thing I would suggest you do is to create a function to do most of the work. The function should accept a string and build the frequency histogram (i.e. count) of all the characters within it. It can then either return the result as an array, or print the details. The main body of the program then just needs to read each line, print the line number (and maybe the line), call the function and see the results.

Rick York · Answer 4 · 2022-09-05T10:42:00

Solution 2

In addition to what Richard stated, I recommend that you accept your input by reading a text file. You can open a file by calling fopen - C++ Reference[^] and you can read lines of text by calling fgets - C++ Reference[^]. That second page has sample code to show you how to use it.

Posted 5-Sep-22 10:42am

Rick York

BernardIE5317 · Answer 5 · 2022-09-05T10:57:00

Solution 3

Writing your own get_line(str) might do the trick

Posted 5-Sep-22 10:57am

BernardIE5317

Updated 6-Sep-22 12:52pm

v2

Comments

Richard MacCutchan 6-Sep-22 11:50am

Possibly, but neither C or C++ has such a function.