C# how do I block / disable double-click event?

Question

5.00/5 (1 vote)

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For my cards game I add a click handler / event to each shuffled card.

The problem is an error when the user double clicks a card.
A single click moves the card to another panel.

            foreach (PlayingCard cardShuffled in cards)
            {
                cardShuffled.Click += card_Click;
. . .

Quote:
System.ArgumentException: "The specified Visual object is already a child of another Visual object or the root of CompositionTarget."

What I have tried:

foreach (PlayingCard cardShuffled in cards)
{
   cardShuffled.MouseDoubleClick += card_Click;
   cardShuffled.Click += card_Click;

Now the problem is that "card_Click" runs twice on card double-click.

Any ideas?

Posted 19-Jun-22 2:56am

Jo_vb.net

Updated 19-Jun-22 4:08am

v2

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Comments

0x01AA 19-Jun-22 9:09am

I think should be easy. In your OnClick handler just Btn.Enabled= false; and at the end back ;)
[Edit]
Btw. why you add a double click handler?

Jo_vb.net 19-Jun-22 9:38am

It is not a button but a PlayingCard class object, which has no enabled property.
And I tried the double click handler only to see if it would help but it does not.

private void card_Click(object sender, EventArgs e)
{
PlayingCard pc = (PlayingCard)sender;

0x01AA 19-Jun-22 9:47am

Then take the dirty way and prevent from reprocessing with a bool...
Something like:


OnClick
{
  if (processing) return;
  processing= true;
  try
  {
    // Do it
  }
  _finally
  {
    procssing= false;
  }
}

Jo_vb.net 19-Jun-22 10:02am

That works fine - thank you.

0x01AA 19-Jun-22 10:20am

You are very welcome.
Pretty incomprehensible to me that you programmed 'Schafkopf' and failed at such a small thing :-)

0x01AA 20-Jun-22 14:04pm

Only a test comment. Please skip it ;)

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0x01AA · Accepted Answer · 2022-06-19T04:08:00

Solution 1

According to the discussions in the comments, there is a 'lazy' solution available:

Prevent from reprocessing with something like that:

OnClick
{
  if (this.processing) return;
  this.processing= true;
  try
  {
    // Do the work here
  }
  _finally
  {
    this.procssing= false;
  }
}

Posted 19-Jun-22 4:08am

0x01AA

Updated 19-Jun-22 4:09am

v2