Why is short -1 not less than unsigned short 0

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C++

The code below generates the output further below. The results for int, long, long long I understand as per implicit integer arithmetic conversions however I do not understand the result of the first test i.e. to wit short as it is first promoted to int and unsigned int per its sign and then the arithmetic conversions but apparently such is not the case. Why?

import std.core;
using namespace std;

template<typename T>
void test()
{
	cout << typeid(T).name() << endl;
	make_signed_t<T> s = -1;
	make_unsigned_t<T> u = 0;
	cout << (s < u) << endl;
	cout << (s + u) << endl << endl;
}

int main()
{
	cout << boolalpha;

	test<short>();
	test<int>();
	test<long>();
	test<long long>();

	return 0;
}

short
true
-1

int
false
4294967295

long
false
4294967295

__int64
false
18446744073709551615

What I have tried:

I read cppreference i.e. to wit in particular
"If the unsigned type has conversion rank greater than or equal to the rank of the signed type, then the operand with the signed type is implicitly converted to the unsigned type."
Implicit conversions - cppreference.com[^]