Whay test function is printing 57?

Question

1.00/5 (1 vote)

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C++

<pre>#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int test (char *param) {
    printf("%d", *param);
}
int main(void){
    char a[]="9009";
    test(a);
}

What I have tried:

I tried many experiments on this code. Still, I don't know why *param is printing 57?

Posted 6-Mar-22 22:20pm

kNIG human

Updated 7-Mar-22 0:09am

v2

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Comments

Richard MacCutchan 7-Mar-22 5:33am

Because that is what you told it to print. If you want the first character of the string then use the %c format type.

_Asif_ 7-Mar-22 6:10am

what do you think it should print?

3 solutions

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Patrice T · Answer 1 · 2022-03-06T22:32:00

Solution 1

Quote:
I tried many experiments on this code. Still, I don't know why *param is printing 57?

57 is the ascii code for "9"
ASCII - Wikipedia[^]

Posted 6-Mar-22 22:32pm

Patrice T

CPallini · Answer 2 · 2022-03-07T00:09:00

Solution 3

You should have written instead

C

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void test (const char * param)
{
    printf("%s\n", param);
}
int main(void)
{
    char a[] = "9009";
    test(a);
    return 0;
}

See printf - C++ Reference[^].

Posted 7-Mar-22 0:09am

CPallini

Comments

Patrice T 7-Mar-22 7:54am

+5

CPallini 7-Mar-22 8:38am

Thank you.

OriginalGriff · Answer 3 · 2022-03-07T00:07:00

Solution 2

See here: printf format string - Wikipedia[^]

Posted 7-Mar-22 0:07am

OriginalGriff