Problem using try catch block in C++

Question

0.00/5 (No votes)

See more:

C++

int x = 1;
     try{
         if(x == 1){
             throw 99;
         }
         cout << "Hey" << endl;
     }
     catch(int err){
         cout << err << endl;
     }

Hey, recently I was studying exception handling in C++ and I wrote the above. However, this code just says terminate called after throwing an instance of 'int'. I guess this should be printing 99. I don't know why this is not working. Please help me. I'll be really grateful. Thank you.

What I have tried:

I have tried searching Google for the correct syntax, but I think my syntax is right and the is not giving the expected output.

Posted 31-Jan-22 2:59am

Siddharth Saurav - IIT [BHU]

Updated 1-Feb-22 7:24am

Sean Ewington

v4

Add a Solution

Comments

Richard MacCutchan 31-Jan-22 9:22am

I just tried that exact code and it works fine. I guess the problem is in the code that you are not showing us.

Greg Utas 31-Jan-22 10:51am

It's not going to fix your problem, whatever it is, but exceptions should be caught by reference: catch(int& err). It won't matter for an int, but it can be important when the exception is an object.

2 solutions

Solution 2

I was doing "#define int long long" to avoid overflow of int in competitive programming. After removing that line it did work. Thanks everyone who replied. :)

Posted 31-Jan-22 6:27am

Siddharth Saurav - IIT [BHU]

Comments

Joe Woodbury 31-Jan-22 17:15pm

The issue aside, why not use int64_t?

Greg Utas 31-Jan-22 20:29pm

Redefining a keyword is naughty. And many uses of #define are undesirable. It's fine in your own code, but not in code that others also use.

CPallini 1-Feb-22 2:11am

"#define int long long"
I hear crying. I hear the God of the C++ programming language crying.

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Accepted Answer · 2022-01-31T03:07:00

If I try it (with minor mods because I don't have your "nl" value):

C++

#include <iostream>

using namespace std;

int main(){
    cout<<"Hello World\n";
    int x = 1;
    try{
        if(x == 1){
            throw 99;
        }
        cout << "Hey\n";
    }
    catch(int err){
        cout << err << "\n";
    }
    cout<<"Goodbye\n";
    return 0;
}

It does exactly what I expected it to:

Hello World
99
Goodbye

...Program finished with exit code 0
Press ENTER to exit console.

So ... what am I doing that you aren't?