I have a problem with the code

Question

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Implement a function that draws a rectangle shape based on the given dimension. This function 
will take two parameters:
• L: Length of the rectangle
• W: Width of the rectangle
Conditions:
• Output shape should be printed using the alphabets, starting with the alphabet ‘a’ on the 
first line, then ‘b’ on the second, ‘c’ on 3rd and so on.
• The casing of the alphabet should change in each column (only columns). The first 
column will have lower case, the 2nd upper case, 3rd lower case again and so on.
• The inside of the rectangle should be empty (fill it with spaces).
The function that draws the rectangle will call 2 functions to help it perform its task.
The first function will be called to handle drawing the top or bottom line. The second function 
will be called to draw middle lines.
(Hint: the lower and upper case ascii of an alphabet character are 32 characters apart)

What I have tried:

#include <iostream>

using namespace std;
void uperline(int d , int l)
{
for (int i=1; i<=d; i++)
    {
        if (i%2==0)
            cout<<"A";

        else
            cout<<"a";}

}
void middlelines (int d , int l)
{
    for (int i=1 ;i <=l-1;i++)
    {  char alpha ='b';
    for(int y=0 ; y==i; y++)
        alpha++;
    cout<<alpha<<endl;

    }
}
int main()
{

    int width ,length;
    cout <<"please enter the length and the width of the rctangle"<<endl;
    cin >> width>> length;
uperline(width , length);
middlelines (width , length);

return 0;

"

I couldn't complete the rest of the columns

"

Posted 15-Dec-21 1:06am

User-15430256

Updated 15-Dec-21 2:00am

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Comments

Richard MacCutchan 15-Dec-21 7:15am

What does that mean? What results do you see when you run the code, and why is it wrong?

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Greg Utas · Answer 1 · 2021-12-15T01:26:00

The question asks you to only use two functions, one of which draws both the upper and lower lines. The character to use therefore needs to be an argument to that function. The character to use could also be an argument to the function that draws the middle lines if you change main to invoke it within a for loop. Also note the hint that if ch is an upper case character, then ch+32 is its lower case equivalent.

CPallini · Answer 2 · 2021-12-15T02:00:00

You may write a function for edge (i.e. top and bottom) lines, like the following:

C++

void edge_line(int row, int length)
{
  for (int col=0; col < length; ++col)
  {
    char c = 'a'+ row - 32 * (col & 1);
    cout << c;
  }
  cout << '\n';
}

Similarly, you may write the code for the middle line function.

Eventually you have to call them:

C++

edge_line(0, length);
for (row = 1; row < (width-1)); ++row)
  middle_line(row, length);
edge_line((width-1), length);

That's all.

I have a problem with the code

2 solutions

Solution 1

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