Insert prepared statement error PHP

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Hey I'm trying to insert something inside my db but its not working I get an error that says

Error: INSERT INTO broodjes (broodnaam, prijs, voorraad) VALUES (?, ?, ?)
You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '?, ?, ?)' at line 1

what am I doing wrong???

this is my form

PHP

<pre><?php include "navbar.php";?>
<link href="https://cdn.jsdelivr.net/npm/bootstrap@5.0.2/dist/css/bootstrap.min.css" rel="stylesheet" integrity="sha384-EVSTQN3/azprG1Anm3QDgpJLIm9Nao0Yz1ztcQTwFspd3yD65VohhpuuCOmLASjC" crossorigin="anonymous">
<style>
    .intro {
  height: 100%;
}

.gradient-custom {
  /* fallback for old browsers */
  background: #fa709a;

  /* Chrome 10-25, Safari 5.1-6 */
  background: -webkit-linear-gradient(to bottom right, rgba(250, 112, 154, 1), rgba(254, 225, 64, 1));

  /* W3C, IE 10+/ Edge, Firefox 16+, Chrome 26+, Opera 12+, Safari 7+ */
  background: linear-gradient(to bottom right, rgba(250, 112, 154, 1), rgba(254, 225, 64, 1))
}
</style>
<section class="intro">
  <div class="mask d-flex align-items-center h-100 gradient-custom">
    <div class="container">
      <div class="row justify-content-center">
        <div class="col-12 col-lg-9 col-xl-7">
          <div class="card">
            <div class="card-body p-4 p-md-5">
              <h3 class="mb-4 pb-2">Nieuwe broodjes toevoegen</h3>

              <form action="insertproduct.php" method="post"><!--Naar de backend om de broodjes te inserten-->

                <div class="row">
                  <div class="col-md-6 mb-4">

                    <div class="form-outline">
                      <input type="text" id="broodjesnaam" name="broodjesnaam" class="form-control" />
                      <label class="form-label" for="broodjesnaam">Broodjes naam</label>
                    </div>

                  </div>
                  <div class="col-md-6 mb-4">

                    <div class="form-outline">
                      <input type="text" id="prijs" name="prijs" class="form-control" />
                      <label class="form-label" for="prijs">Prijs</label>
                    </div>

                  </div>
                </div>

                <div class="row">
                  <div class="col-md-6 mb-4">

                    <div class="form-outline">
                      <input type="text" id="voorraad" name="voorraad" class="form-control" />
                      <label class="form-label" for="voorraad">Voorraad</label>
                    </div>

                  </div>
                  <!--Dit zou nog de images kunnen zijn maar dat doe ik pas later-->
                  <!-- <div class="col-md-6 mb-4">

                    <div class="form-outline">
                      <input type="tel" id="phoneNumber" class="form-control" />
                      <label class="form-label" for="phoneNumber">Phone Number</label>
                    </div>

                  </div> -->
                </div>

                <div class="row">
                  <div class="col-12">

                    <div class="mt-4">
                      <input class="btn btn-warning btn-lg" type="submit" value="Toevoegen" />
                    </div>

                  </div>
                </div>

              </form>
            </div>
          </div>
        </div>
      </div>
    </div>
  </div>
</section>
<?php include "footer.php";?>

this is my backend code

PHP

<pre><!--inserting data -->
<?php
include "config.php";
$broodnaam = $_POST['broodjesnaam'];
$prijs =  $_POST['prijs'];
$voorraad =  $_POST['voorraad'];

$sql = "INSERT INTO broodjes (broodnaam, prijs, voorraad) VALUES (?, ?, ?)";
$stmt = $conn->prepare($sql);
$stmt->bind_param("sii", $broodnaam, $prijs, $voorraad);
$stmt->execute();

if ($conn->query($sql) === TRUE) {
  echo "New record created successfully";
} else {
  echo "Error: " . $sql . "<br>" . $conn->error;
}

$conn->close();
?>

What I have tried:

I have tried looking up examples for prepared statements but to me it looks the same as I have

Posted 7-Dec-21 0:03am

Rebecca2002

Updated 7-Dec-21 0:17am

v2

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Chris Copeland · Accepted Answer · 2021-12-07T00:17:00

The issue is:

PHP

$stmt->bind_param("sii", $broodnaam, $prijs, $voorraad);
$stmt->execute();

if ($conn->query($sql) === TRUE) { <-- here

You're creating a prepared statement, binding your parameters, and then executing it with $stmt->execute(); but then you're trying to execute your SQL again using $conn->query($sql) which is incorrect. You should be checking the return value of the execute() method instead:

PHP

$stmt->bind_param("sii", $broodnaam, $prijs, $voorraad);

if ($stmt->execute() === TRUE) {