I need explanation on this code

Question

1.44/5 (3 votes)

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i need explanation on this code for each part and why the answer is 8 4 4 on c language

#include<stdio.h>

int main(){
printf("%d\t",sizeof(6.5));
printf("%d\t",sizeof(90000));
printf("%d",sizeof('A'));

return 0;
}

What I have tried:

i tried to figure it out but still has no clue i need answer asap

Posted 26-Oct-21 5:48am

Silver 2021

Updated 26-Oct-21 5:57am

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2 solutions

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Richard MacCutchan · Accepted Answer · 2021-10-26T05:54:00

Solution 1

The sizeof operator returns the size of the variable or object provided. In your case you are asking fo the size of i) a double type, ii) an int, ~~and iii) a character~~. See Storage of Basic Types | Microsoft Docs[^] for the actual sizes.

[edit]
as noted by OriginalGriff, the third item is treated as an int type.
[/edit]

Posted 26-Oct-21 5:54am

Richard MacCutchan

Updated 26-Oct-21 6:07am

v2

Comments

OriginalGriff 26-Oct-21 12:00pm

"iii) a character"
Not so - 'A' is an integer by default - hence the length of 4.
(It's a legacy thing from the first days of the C language)

Richard MacCutchan 26-Oct-21 12:08pm

Corrected. And yes, I really should know that. :(

OriginalGriff 26-Oct-21 12:46pm

Easy thing to forget! :laugh:

CPallini 26-Oct-21 14:05pm

5.

Richard MacCutchan 26-Oct-21 14:17pm

Thanks, although only 66.6% right. :(

Member 15329613 26-Oct-21 16:30pm

In baseball that would be amazing.

OriginalGriff · Accepted Answer · 2021-10-26T05:57:00

Solution 2

6.5 is a double: 8 bytes long.
90000 is an int: 4 bytes long.
'A' is a int: 4 bytes long.
Try this:

C

char a = 'a';
printf("%zu\n",sizeof('a'));
printf("%zu",sizeof(a));

Posted 26-Oct-21 5:57am

OriginalGriff

Comments

CPallini 26-Oct-21 14:05pm

5.