I need clarification why the new keyword is used in this code

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Java

Hello everyone, please why is the keyword "new" used in returning a new array in leetcode's question number 1 (twoSum).

Question - Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

Brute Force Solution -

public class TwoSum {

    public static void main(String[] args) {

        int[] nums = {2, 5, 9, 7};

        twoSum(nums, 9);  
    }

    public static int[] twoSum(int[] nums, int target) {

        for (int i = 0; i < nums.length; i++) {
            for (int j = i + 1; j < nums.length; j++) {
                if (nums[i] + nums[j] == target) {
                    System.out.println("fisrtIndex is " + i + " secondIndex is  " + j);
                    return new int[]{i, j};
                }
            }
        }
        return new int[]{};
      }
	}

My question is, why do we have to use the keyword "new" when returning a new integer array here(

return new int[]{i, j};

) when the class TwoSum doesn't extend the Arrays class in java?

How come we can create a new instance of an Array without extending the class Arrays in java?
The int in (return new int[] {i, j}) shows the return type but why use the keyword "new"?
I hope my question is clear, thanks for any help.

What I have tried:

public static int[] twoSum(int[] nums, int target) {

    for (int i = 0; i < nums.length; i++) {
        for (int j = i + 1; j < nums.length; j++) {
            if (nums[i] + nums[j] == target) {
                System.out.println("fisrtIndex is " + i + " secondIndex is  " + j);
                return new int[]{i, j};
            }
        }
    }
    return new int[]{};
  }