How to extract second address value in C++

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below is the string value i am getting and i want to store the second address value in a variable and n case it only return one address the first one then it shouldn't store this address

Server:  resolver1.opendns.com
Address:  202.62.333.112

Non-authoritative answer:
Name:    myip.opendns.com
Address:  19.40.22.46

i only want to store the second address in a variable which is 19.40.22.46

What I have tried:

C++

istringstream is3(result);
const string Pattern = "Address:";

//result is the variable in which i wil get above output
// string line;

// const size_t Len = Pattern.length();
string ipchk;
// string line98;

while (getline(is3, line98))
{
    if (line98.find(Pattern) != string::npos)
    {

        line98.erase(0, 39);
        ipchk = line98.erase(line98.size() - 1);

        //ipchk = line98.substr(Len);
        // return line98.substr(Len);
        Ipv4 = ipchk;
        break;
    }
}
IpAddress=Ipv4;

Posted 1-Mar-20 22:42pm

Member 12899279

Updated 2-Mar-20 2:18am

Stefan_Lang

v2

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Richard MacCutchan 2-Mar-20 5:06am

And?
What have you tried?
Where are you stuck?

Member 12899279 2-Mar-20 6:39am

istringstream is3(result);
const string Pattern = "Address:";

//result is the variable in which i wil get above output
// string line;

// const size_t Len = Pattern.length();
string ipchk;
// string line98;

while (getline(is3, line98))
{
if (line98.find(Pattern) != string::npos)
{

line98.erase(0, 39);
ipchk = line98.erase(line98.size() - 1);

//ipchk = line98.substr(Len);
// return line98.substr(Len);
Ipv4 = ipchk;
break;
}
}
IpAddress=Ipv4;

this

Richard MacCutchan 2-Mar-20 6:46am

So what is the problem?

Stefan_Lang 2-Mar-20 7:20am

That is the kind of info you should have added to your question with the [Improve question] button at the lower right of your question.

This time I did it for you, and restored some formatting to make it readable too.

That said, this code is incomplete, and not very helpful to understand what your problem is. If you're stuck, you should put a little more effort into explaining where.

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phil.o · Answer 1 · 2020-03-02T02:18:00

Solution 1

A regular expression would be perfect to isolate the second result:

C++

#include <regex>

std::regex r("^Address:\s+((?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)(\.|$)){4})$");
std::smatch match;
std::string address;

if (std::regex_match(result, match, r))
{
   address = match[match.size() > 1 ? 1 : 0]; // The second result, if more than one, or the first result
}

Posted 2-Mar-20 2:18am

phil.o

Updated 2-Mar-20 3:06am

v2

Comments

Member 12899279 2-Mar-20 9:01am

its not even going inside the loop i think regex is incorrect btw thanks for trying

Stefan_Lang 2-Mar-20 10:15am

I'm not very familiar with Regex, but I think you are supposed to concatenate all lines and let the Regex extract the resulting the addresses from the multiline string. No loop required.