How to fix parse error:syntax errorunexpected end of file on line number 69

<?php 

include("admin/config/db.php");
?>
<div class="col-md-4">
<div class="side">
<div class="side_main">
<span>Latest Post</span></div>
</div><br>
<?php

$select="select * from news order by id Desc limit 0,4";
$run=mysqli_query($con,$select);
$count=mysqli_num_rows($run);
if(count>0){

while($row=mysqli_fetch_array($run)){
	
	$id=$row['id'];
	$name=$row['Name'];
	$img=$row['Image'];


?>
<div class="row">

<div class="col-md-4"><br><img src="admin/<?php echo $img?> " class ="img img-rounded" style="width:120px; height:120px; border:1px solid;"><br><br></div>

<div class="col-md-4"><span class="side_post"><a href="viewnews.php?id=<?php echo $id?>"><?php echo $name?></a></div>
</div></div><hr>
<?php}}
else{
	
echo "<center><h5>Sorry No Post Available </h5></center>";
}
?>
<div class="col-md-4">

<div class="side">
		<div class="side_main">
			<span>Categories</span>
</div>
<div class="cat">
	<?php  

$cat="select * from cat order by id desc";
$run_cat=mysqli_query($con,$cat);
$count_cat=mysqli_num_rows($run_cat);
if($count_cat>0){

	while($row=mysqli_fetch_array($run_cat)){

		$id_cat=$row_cat['id'];
		$name_cat=$row_cat['Name'];

		?>
	<a href="all.php?id=<?php echo $id_cat ?>"><?php echo $name_cat ?> </a>
	<?php }}


	else{

echo "<center><h5>Sorry No Categories Available </h5></center>";

	}


	?>
</div>