Comments by Guilherme Romero

Guilherme Romero 7-Feb-23 23:12pm View

Thanks a lot, it really worked. But the compiler of the course I'm doing doesn't allow me to use a function. I'm supposed to print the output directly whereas the compiler gives the input. So I changed the code a little and it became like this:
' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' '
s = 'hzixbdqmdljvb'
max_length = 0
current_length = 0
start = 0
max_start = 0
for i in range(len(s) - 1):
if ord(s[i + 1]) >= ord(s[i]):
current_length += 1
else:
if current_length > max_length:
max_length = current_length
max_start = start
start = i + 1
current_length = 0
if current_length > max_length:
max_length = current_length
max_start = start

print('max_start:', max_start)
print('max_length:', max_length)
print('Longest substring in alphabetical order is: ',s[max_start:max_start + max_length + 1])
' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' '

It does work in some cases, but it doesn't in most of them. In this case, when the input is s = 'hzixbdqmdljvb', the answer should be 'bdq' but I got 'ixbd'.
As you can see, I added print(max_start) and print(max_length) to see what happens. If you run the code, you'll see that max_start and max_length are different than they should.
Could you please help me in this case?
Thanks.

Guilherme Romero 7-Feb-23 20:59pm View

Deleted

Thanks a lot.
It's working with some inputs, but not all of them.
For example, if s = 'jsvdyshlfcoypgtdud', the expected output is 'jsv', but the given answer is 'dyshl'
The same happens with s = 'vosssitenez', the real output is 'oss', but the output given is 'voss'
Or if s = 'cotojwhbzqrslew', the correct answer is 'cot', but it's giving 'ojwhb'.

Guilherme Romero 28-Jan-23 12:26pm View

Ok, thank you.

Guilherme Romero 28-Jan-23 12:12pm View

Thanks very much! Now "counts" is correct:
[('04', 3), ('06', 1), ('07', 1), ('09', 2), ('10', 3), ('11', 6), ('14', 1), ('15', 2), ('16', 4), ('17', 2), ('18', 1), ('19', 1)]

But still I'm getting a horizontal list instead of a vertical column. Do you know how to do it?

Thanks.

Guilherme Romero 28-Jan-23 11:44am View

I've inserted the link to the data on the statement above.

The code I'm now using is this:

name = input("Enter file:")
if len(name) < 1:
name = "mbox-short.txt"
handle = open(name)
counts = dict();

for line in handle:
if line.startswith('From:'):
pass

elif line.startswith('From'):
x = line.split();
time = x[5];
t = time.split(':');
hour = t[0];
for line in hour:
counts[hour] = counts.get(hour,0) + 1;

print(sorted(counts.items()));

Guilherme Romero 28-Jan-23 11:19am View

Hello,
Your solution worked partially.
The output I'm getting now is:

[('04', 6), ('06', 2), ('07', 2), ('09', 4), ('10', 6), ('11', 12), ('14', 2), ('15', 4), ('16', 8), ('17', 4), ('18', 2), ('19', 2)]

As you can see, the hours (first numbers in each parethesis) are sorted correctly, but the "counts" is double the value that it should be. If you compare it to the answer, you'll see that "counts" for 04 is 6, where it should be 3. "Counts" for 06 is 2, where it should be 1, and so on for all the other items.
Another issue is that now the output is a horizontal list, where it should be a vertical column, as shown in the answer.
Could you help me with that?

Thank you.

Guilherme Romero 22-Jan-23 9:21am View

No, I'm talking about Javascript. In the online GDB compiler , there's an option for using JAvascript(Rhino) as a language.

Guilherme Romero 22-Jan-23 9:21am View

Deleted

No, I'm talking about Javascript. In the online GDB compiler , there's an option for using JAvascript(Rhino) as a language.

Guilherme Romero 21-Jan-23 10:08am View

Thanks very much, it worked!

Guilherme Romero 21-Jan-23 9:51am View

Deleted

Thanks very much, it worked!
But could you please explain me how the right part of the lines ( the dates) were removed wothout rstrip()? Thanks.

Comments by Guilherme Romero (Top 10 by date)