Comments by Member 12177493 (Top 1 by date)

Member 12177493 3-Dec-15 9:02am View

Shall I write my batch file as below after my rmcobol compilation?

runcobol PROGRAM1.COB /usr/rmcobol/indata/FILE1 /usr/rmcobol/outdata/file1.txt
runcobol PROGRAM2.COB /usr/rmcobol/indata/FILE2 /usr/rmcobol/outdata/file2.txt
runcobol PROGRAM3.COB /usr/rmcobol/indata/FILE3 /usr/rmcobol/outdata/file3.txt
runcobol PROGRAM4.COB /usr/rmcobol/indata/FILE4 /usr/rmcobol/outdata/file4.txt
runcobol PROGRAM5.COB /usr/rmcobol/indata/FILE5 /usr/rmcobol/outdata/file5.txt
runcobol PROGRAM6.COB /usr/rmcobol/indata/FILE6 /usr/rmcobol/outdata/file6.txt
runcobol PROGRAM7.COB /usr/rmcobol/indata/FILE7 /usr/rmcobol/outdata/file7.txt
runcobol PROGRAM8.COB /usr/rmcobol/indata/FILE8 /usr/rmcobol/outdata/file8.txt

My question is here - How do i pass every input/output path to cobol program in runtime.

I think we need to do with Linkage section to pass variable in runtime. I am not sure this concept. How will I tell this to unix that this is my input path/output path of COBOL program when run time?

Hope I am not confused you :)