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I'm not sure I follow exactly what you are trying to do, but if your data entry form is accessible from the data table form, just make the input text public and read it from the data table form.
If that's not what you need, then perhaps you could explaining your dilemma a little better and let us know what you've tried so far.
CQ de W5ALT
Walt Fair, Jr., P. E.
Comport Computing
Specializing in Technical Engineering Software
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Let me simplify things a bit to be more clear. Let's say I have two forms. There is a textbox on Form1 and I'll just have some default text that resides in the textbox. On Form1_Load shown below, frmCalData is instantiated and shown. frmCaldata has a dataset dsCalData with a data table tblCalData.
private void Form1_Load(object sender, EventArgs e)
frmCalData frmCal = new frmCalData();
frmCal.Show();
I believe I should be eventually calling out something like this:
DataRow row = tblCalData.NewRow();
tblCalData.Rows.Add(textbox1.Text);
However, in the Form1_Load method, I cannot call out tblCalData.
As this is new to me, I am shooting somewhat blind, so any guidance will be greatly appreciated.
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When you try to access tblCalData from Form1, what happens? If it gives you an error, what error is shown?
You should be able to access tblCalData from Form1 as frmCal.tblCalData, but it will need to be set public for it to be accessible.
On the other hand, is there a reason that you need both in 2 separate forms?
CQ de W5ALT
Walt Fair, Jr., P. E.
Comport Computing
Specializing in Technical Engineering Software
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DataRow row = frmCal.dataTable1.NewRow (label4.Text,"0","0");
frmCal.dataTable1.Rows.Add(row);
The error is that 'NewRow' Takes '3' arguments. However, there are three columns and the NewRow method indicates that it will create the same schema as the table so I thought I'd have to have place markers for the other two columns.
I have a separate form for just the data table from the main user interface form.
Updated:
Just changed the above to:
DataRow row = frmCal.dataTable1.NewRow();
row[0] = label4.Text;
frmCal.dataTable1.Rows.Add(row);
That works fine. Thanks for keeping me scratching my head 
modified on Wednesday, May 5, 2010 10:07 PM
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I know how it goes - sometimes it can be frustrating figuring things out, but it feels so nice when it finally works. 
Glad to hear you got it working!
CQ de W5ALT
Walt Fair, Jr., P. E.
Comport Computing
Specializing in Technical Engineering Software
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I have the following class:
class Program
{
static void Main()
{
}
public enum AnimType
{
StickMan
}
public enum StickMan
{
Walk,Run
}
}
This class is used to demo-straight the problem im trying to solve at a simplistic level as otherwise I would have to paste lots of code which is never good.
So that I could use :
Dictionary<(AnimType,STickMan),Animation> animation = new Dictionary<(AnimType,STickMan)();
to get this working:
animation .Add(AnimType.StickMan,StickMan.Walk,new WalkAnimation());
This would allow me to return an Animation object depending on what the animation type (stickman) and the unique animation states (walk,run).
I know that the syntax used for this dictionary is incorrect but its the best way I know how to display it so sorry in advance! 
modified on Wednesday, May 5, 2010 2:17 PM
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I would suggest breaking this down a bit more logically... Assuming you plan on adding more animation types, each with its own list of animations, you're going to have a huge collection of enums and no real organization at all... So here's what I would do...
Make a StickMan class, and have it implement a common interface (So you can add more similar classes later)... Let's just call it IAnimationContainer, for example:
public interface IAnimationContainer
{
Animation GetAnimation(string name);
}
public class StickMan : IAnimationContainer
{
private Dictionary<string, Animation> _animations = new Dictionary<string, Animation>();
public StickMan()
{
_animations.Add("Walk", new WalkAnimation());
}
public Animation GetAnimation(string name)
{
return _animations[name];
}
}
Then, you use your dictionary to index AnimTypes to the actual classes...
animations.Add(AnimType.StickMan, new StickMan());
And to get the actual animation:
animations[AnimType.StickMan].GetAnimation("Walk");
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That is brilliant, I have had a hard long day and feel pretty stupid now
...4 Exams in one day !
Thanks !
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can you correct this document the code pls ,thanks
namespace eControlCevertest.lib.Primitives
{/// <summary>
/// la class Gline est un class mere
/// </summary>
public sealed class GLine
{
#region Variables
private bool m_IsDataCorrect;
private LineDefinition m_ContentFormat;
private short
m_CRCComputed = -1,
m_CRCGiven = -1;
private string
m_Code,
m_Value;
#endregion
#region public Accessors
/// <summary>
/// Contient le Code de la donnée etdonne la v aleur, conformement au CDC GiEGLAN
/// </summary>
public string Code
{
get { return m_Code; }
set { m_Code = value; }
}
public LineDefinition ContentFormat
{
get { return m_ContentFormat; }
set { m_ContentFormat = value; }
}
/// <summary>
/// Contient la valeur de la donnée et calcule le ,
/// </summary>
public string Value
{
get { return m_Value; }
set
{
m_Value = value;
ComputeState();
}
}
public short CRCComputed
{
get
{
return m_CRCComputed;
}
}
public short CRCGiven
{
get { return m_CRCGiven; }
set
{
m_CRCGiven = value;
ComputeState();
}
}
public bool IsDataCorrect
{
get
{
return m_CRCGiven != -1 && m_IsDataCorrect;
}
}
/// <summary>
///
/// </summary>
public bool IsDefinitionAvailable
{
get
{
return m_ContentFormat != null;
}
}
#endregion
#region public non default Constructs
/// <summary>
// Constructeurs
/// </summary>
public GLine(string code, string value, short givencrc)
{
m_Code = code;
m_Value = value;
m_CRCGiven = givencrc;
ComputeState();
}
/// <summary>
// Constructeurs .
/// </summary>
public GLine(string code, string value)
{
m_Code = code;
m_Value = value;
m_CRCComputed = Common.CalcCRC(value);
}
/// <summary>
// Constructeurs .
/// </summary>
public GLine(string code, LineDefinition definition)
{
m_Code = code;
m_ContentFormat = definition;
}
#endregion
/// <summary>
/// fonction pour Calculer les valeurs.
/// </summary>
private void ComputeState()
{
m_CRCComputed = Common.CalcCRC(m_Value);
m_IsDataCorrect = m_CRCGiven == m_CRCComputed;
}
}
}
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What do you mean? Edit your question to make it descriptive and post only the relevant code within "pre" tags.
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toto_2010 wrote: can you correct this document the code pls ,thanks
I appreciate that English is probably not your first language, but can you try rewording this to make a clearer question?
It's time for a new signature.
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toto_2010 wrote: can you correct this document the code pls
Without us knowing what you are trying to achieve here, and what the problem you are having is, then no. I will tell you though that you have a potential issue in your code when you set a property and then call ComputeState. What happens if you don't actually change the value, but reassign one that's already there?
"WPF has many lovers. It's a veritable porn star!" - Josh Smith As Braveheart once said, "You can take our freedom but you'll never take our Hobnobs!" - Martin Hughes.
My blog | My articles | MoXAML PowerToys | Onyx
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Noone is going to fix your code or write your documentation for you. We can point you in the right direction, but you have to ask a question we can understand first.
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I derived following code from your distorted code.
public sealed class GLine
{
#region Variables
private bool m_IsDataCorrect;
private LineDefinition m_ContentFormat;
private short m_CRCComputed = -1, m_CRCGiven = -1;
private string m_Code, m_Value;
#endregion
#region public Accessors
public string Code
{
get { return m_Code; }
set { m_Code = value; }
}
public LineDefinition ContentFormat
{
get { return m_ContentFormat; }
set { m_ContentFormat = value; }
}
public string Value
{
get { return m_Value; }
set
{
m_Value = value;
ComputeState();
}
}
public short CRCComputed
{
get
{
return m_CRCComputed;
}
}
public short CRCGiven
{
get { return m_CRCGiven; }
set
{
m_CRCGiven = value;
ComputeState();
}
}
public bool IsDataCorrect
{
get
{
return m_CRCGiven != -1 && m_IsDataCorrect;
}
}
public bool IsDefinitionAvailable
{
get
{
return m_ContentFormat != null;
}
}
#endregion
#region public non default Constructs
public GLine(string code, string value, short givencrc)
{
m_Code = code;
m_Value = value;
m_CRCGiven = givencrc;
ComputeState();
}
public GLine(string code, string value)
{
m_Code = code;
m_Value = value;
m_CRCComputed = Common.CalcCRC(value);
}
public GLine(string code, LineDefinition definition)
{
m_Code = code;
m_ContentFormat = definition;
}
#endregion
private void ComputeState()
{
m_CRCComputed = Common.CalcCRC(m_Value);
m_IsDataCorrect = m_CRCGiven == m_CRCComputed;
}
}
So unable to find what is exact problem with
this code...
Hope this will help!
Jinal Desai - LIVE
Experience is mother of sage....
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Hi all,
I am facing problem in displaying the Date formate in Excel .
From Database i am displaying the Date lets say the Formate "dd/mm/yy" e.g 03/05/10. nothing but (3rd May 2010)
The above formate is displaying in correctly in English settings but when the client generating the excel, there it is displaying as "05/03/10" i mean day and month are interchanging.
(Because they are using Italian settings due to this reason date is displaying like 05/03/10)
Can any body help on this?Date formate should not interchange
Thanks in advance,
Balu.
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I would leave it as is.
They have Italian settings for a reason (are they Italian perhaps) so they will want dates to show in the Italian format.
The only time I think it is legitimate to force a date format is with regard to American settings when coding for British users. Unfortunately Microsoft in their wisdom default English settings to be American English, even on editions of software produced specifically for the British market. Consequently many British people have American settings by mistake. This is especially a problem with SQL Server, which will not install in British English no matter how hard you try (causing no end of trouble with reporting services), and must be changed afterwards. In fact only the execution language can be changed, the root installed language settings cannot be changed! All other culture settings should be respected.
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I am trying to parse the following JSON string, to get the genre, id, and photo in a list.
[
{
id: "6"
genre: "Music"
photo: "music.jpg"
},
{
id: "2"
genre: "Entertainment"
photo: "enter.png"
},
{
id: "8"
genre: "Games"
photo: "games.gif"
},
{
id: "7"
genre: "Movies"
photo: "movie.gif"
},
{
id: "9"
genre: "News"
photo: "news.jpg"
},
{
id: "5"
genre: "Mail"
photo: "Mail.gif"
}
]
I tried using the JSON.Net library, but could not really use it, due to lack of examples.
If anyone can help in getting the id, genre, and photo in a list, that would be really helpful!
*Also, I am using the Compact Framework, WM 6.
Thanks,
Harsimran Singh
1) The good news about computers is that they do what you tell them to do. The bad news is that they do what you tell them to do. - Ted Nelson
2) Why is it drug addicts and computer afficionados are both called users? - Clifford Stoll
3) The real danger is not that computers will begin to think like men, but that men will begin to think like computers. - Sydney J. Harris
(Computer code: 00001111 - translation: Hello! :P )
REMEMBER:
"Computers are made for us, we are not made for them
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Have you looked at JavaScript Object Notation Support for .NET 2.0[^]
You should never use standby on an elephant. It always crashes when you lift the ears. - Mark Wallace
C/C++ (I dont see a huge difference between them, and the 'benefits' of C++ are questionable, who needs inheritance when you have copy and paste) - fat_boy
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The JSON.Net library isn't too hard to use. The documentation can be a bit hard to follow at times, but at lot of the mess comes from the really bad LINQ examples.
Create a class to encapsulate the id, genre, and photo fields. I'll just call it Section for this example. Then use this code to get your list of Section objects:
List<Section> products = JsonConvert.DeserializeObject<List<Section>>(jsonString);
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Thanks!
That worked perfectly for me!!
1) The good news about computers is that they do what you tell them to do. The bad news is that they do what you tell them to do. - Ted Nelson
2) Why is it drug addicts and computer afficionados are both called users? - Clifford Stoll
3) The real danger is not that computers will begin to think like men, but that men will begin to think like computers. - Sydney J. Harris
(Computer code: 00001111 - translation: Hello! :P )
REMEMBER:
"Computers are made for us, we are not made for them
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Hi
In my application i am trying to play up to 12 videos simultaneously and I am accessing the videos on a mapped network drive. Can someone please point me at some literature or some examples of buffering video files.
Thanx
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